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hjlf
3 years ago
10

The first part of this experiment involved the calibration of the equipment you will use to measure the rate of oxygen evolution

. To do so, you will inject air into the sealed reaction bottle at known temperatures and measure the pressure change within the bottle. Suppose 30.0 mL of air at an initial temperature of 22.5 ºC and an initial pressure of 0.966 atm was injected into a reaction bottle that contained 30.0 mL of water. Use this information to answer the following questions.
(a) How many moles of air are contained in the syringe?
(b) Pretend the gas you injected escaped into the air above the 30.0 mL of water within the vessel. If the gas had remained in the water, what would its "molar concentration" have been?
(c) If the pressure in the flask is observed to be 1.088 atm with no change in temperature after the injection (or after the "escape" from the 30 mL of water in the vessel in our pretend scenario in part B), what is the molar concentration-to-pressure change ratio? This value can be used to convert a change in pressure within the vessel to a molar concentration of gas that escaped from the solution or vice versa. This factor will be used in questions 2 and 3 below.
Chemistry
1 answer:
kirza4 [7]3 years ago
4 0

Answer:

Explanation:

(3 pts) A 5.00 gram sample of an oxide of lead PbxOy contains 4.33 g of lead.  Determine the  

   simplest formula for the compound.

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A solution is prepared by pipetting 20.00 mL of a 1.00 x 10-3 M NaCl solution into a 250.0 mL volumetric flask. The flask is dil
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Answer:

The concentration of the newly prepared solution is 8 * 10^-5 M

Explanation:

The most common way to solve this problem is to use the following formula

c1*V1 = c2*V2

with c1 = 1 * 10^-3 M

with V1 = 20 mL = 0.02 L

with c2 = TO BE DETERMINED

with V2 = 250 mL = O.250 L

10^-3 * 0.02 L = c2 * 0.250L

0.00002 = c2 * 0.250L

c2 = 0.00002 / 0.250 L

c2 = 0.00008 M = 8 * 10^-5 M

The concentration of the newly prepared solution is 8 * 10^-5 M

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3 years ago
The graph models the amount remaining, in milligrams, of a radioactive substance as a function of time, in years. Explain the me
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3 years ago
Boyles Law-
My name is Ann [436]

Answer:

<u>Boyles Law-</u>

Variables that change: volume and pressure

Variables that remain constant: Temperature

<u>Charles Law-</u>

Variables that change: volume and temperature

Variables that remain constant: pressure

Explanation:

5 0
3 years ago
draw two lewis structures for a compound with the formula c4h10 . no atom bears a charge, and all carbon atoms have complete oct
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The number of sigma bonds = 5, and number of pi bonds = 3 in the given compound. Shown in attachment are the two Lewis structures of the compound with molecular formula C4H10. The two structures are the isomers of each other.

Butane is an alkane represented by C4H10. All the bonds in this situation are single bonds because this substance is an alkane. Two shared electrons are present in every bond.

Each carbon atom requires 8 electrons around it in order to follow the Octet Rule. The octet rule was completed by the hydrogen bonds, eliminating the need for the electron dots.

Straight-chained butane is the first structure. The y-chained isobutane is the second structure.

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