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Zarrin [17]
3 years ago
8

Please help me with this :)

Mathematics
1 answer:
ELEN [110]3 years ago
3 0

Answer:

It is the answer C

Step-by-step explanation:

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Two lockers, 35 and 70
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Find the 52nd term of the arithmetic sequence ?
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不完整的问题,对不起,伙计。

本题已由中国数学会官方解答(现有会员:2人)

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Help me find the answer to this please. And also explain how to slove these problems.​
Evgen [1.6K]

Answer:

B and C

Step-by-step explanation:

Minimum and Maximum points occur when the gradient of the function is equal to 0. Graphically this looks like a bend such that the function dips from decreasing to increasing (the gradient goes form being negative to positive) and vice versa.

A minimum point occurs where all the nearby values are higher than that of the point in question.

A maximum point occurs where all the nearby points are lower than the point in question.

By looking at the graph, there is a maximum point around (4.5, 1.5) which is consistent with B but not A (since A talks about a minimum point)

By looking at the graph, there is a minimum point around (0.5, 1.5) which is consistent with C.

I've highlighted areas of interest below so hopefully that's helpful :>

6 0
2 years ago
Find parametric equations for the path of a particle that moves along the circle x2 + (y − 1)2 = 16 in the manner described. (En
ArbitrLikvidat [17]

Answer:

a) x = 4\cdot \cos t, y = 1 + 4\cdot \sin t, b) x = 4\cdot \cos t, y = 1 + 4\cdot \sin t, c) x = 4\cdot \cos \left(t+\frac{\pi}{2}  \right), y = 1 + 4\cdot \sin \left(t + \frac{\pi}{2} \right).

Step-by-step explanation:

The equation of the circle is:

x^{2} + (y-1)^{2} = 16

After some algebraic and trigonometric handling:

\frac{x^{2}}{16} + \frac{(y-1)^{2}}{16} = 1

\frac{x^{2}}{16} + \frac{(y-1)^{2}}{16} = \cos^{2} t + \sin^{2} t

Where:

\frac{x}{4} = \cos t

\frac{y-1}{4} = \sin t

Finally,

x = 4\cdot \cos t

y = 1 + 4\cdot \sin t

a) x = 4\cdot \cos t, y = 1 + 4\cdot \sin t.

b) x = 4\cdot \cos t, y = 1 + 4\cdot \sin t.

c) x = 4\cdot \cos t'', y = 1 + 4\cdot \sin t''

Where:

4\cdot \cos t' = 0

1 + 4\cdot \sin t' = 5

The solution is t' = \frac{\pi}{2}

The parametric equations are:

x = 4\cdot \cos \left(t+\frac{\pi}{2}  \right)

y = 1 + 4\cdot \sin \left(t + \frac{\pi}{2} \right)

7 0
3 years ago
Match each subtraction problem on the left with the equivalent simplified expression on the right.
Ahat [919]

Answer:

A-3, B-4, C-1, D-2

Step-by-step explanation:

A:

  • 5x-(3x+1)
  • Expand, 5x-3x-1
  • Combine like terms, 2x-1

B:

  • 5x-(-3x-1)
  • Expand, 5x+3x+1
  • Combine like terms, 8x+1

C:

  • -5x-(3x+1)
  • Expand, -5x-3x-1
  • Combine like terms, -8x-1

D:

  • -5x-(-3x-1)
  • Expand, -5x+3x+1
  • Combine like terms, -2x+1

4 0
2 years ago
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