Answer:
thats not a question, that is a statement
Step-by-step explanation:
Let us say that:
a = ones
b = fives
c = twenties
So that the total money is:
1 * a + 5 * b + 20 * c = 229
=> a + 5b + 20c = 229 -->
eqtn 1
We are also given that:
c = a – 5 -->
eqtn 2
a + b + c = 30 -->
eqtn 3
Rewriting eqtn 3 in terms of b:
b = 30 – a – c
Plugging in eqtn 2 into this:
b = 30 – a – (a – 5)
b = 35 – 2a -->
eqtn 4
Plugging in eqtn 2 and 4 into eqtn 1:
a + 5(35 – 2a) + 20(a – 5) = 229
a + 175 – 10a + 20a – 100 = 229
11a = 154
a = 14
So,
b = 35 – 2a = 7
c = a – 5 = 9
Therefore there are 14 ones, 7 fives, and 9 twenties.
Answer:
I think the answer is:
-Y = 7
-Z = 10.63
-X = 9.22
Step-by-step explanation:
Hope this helps!
:)
The answer is 88 5/6 . If you were stuck try turning the fractions into improper fractions and multiply both of them and later divide the numerator by the denominator to have a mixed number. You can later simplify the fraction to get 88 5/6. If you need help don't be afraid to tell me in the comments! Hope this helps :)
