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3 years ago

Can anybody help? Having a little trouble with this during quarantine...

Mathematics

1 answer:

kolbaska11 [484]3 years ago

6 0

First you would have to find the base which would be 9^2 + 9^2= C^2 because of the pythagorean theorem. So the base would equal 12.7. To find the area of a triangle it’s A= h•b / 2. So your answer would be 95.25

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The answer is C. all the savings added up is $450. 1 percent of 3,470 is $34.7. $450/$34.7 is 12.9682997, which rounded up is 13.

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3 years ago

HELP DUE AT 8:30 I NEED To Do DIS

lbvjy [14]

Answer:

Step-by-step explanation:

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2 years ago

An observational study that draws information about how many runners in a

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3 years ago

Please help!! 10 point available:)

salantis [7]

Answer:

$1) - 2n + 14$

$2)- 5n + 30$

Step-by-step explanation:

$n = a + (n - 1) \times d \\ = 12 + (n - 1) \times - 2 \\ = 12 - 2n + 2 \\ = - 2n + 14$

$n = a + (n - 1) \times d \\ = 25 + (n - 1) \times - 5 \\ = 25 - 5n + 5 \\ = - 5n + 30$

Can I have the brainliest please?

8 0

3 years ago

Can somebody help me on 23 and 24, it’s geometry

Luda [366]

Question 23:

x = 4

DE = 44

Question 24:

x = 25

SE = 28

Step-by-step explanation:

As RS is the perpendicular bisector of DE, it will divide DE in two equal parts DS and SE

Question number 23:

Given

DS = 3x+10

SE = 6x-2

As the two segments are equal:

$DS = SE\\3x+10 = 6x-2$

Subtracting 10 from both sides

$3x+10-10 = 6x-2-10\\3x = 6x-12$

subtracting 6x from both sides

$3x -6x = 6x-6x-12\\-3x = -12$

Dividing both sides by -3

$\frac{-3x}{-3} = \frac{-12}{-3}\\x = 4$

Now

$DS = 3x+10\\= 3(4)+10\\= 12+10\\=22$

And

$SE = 6x-2\\= 6(4)-2\\= 24 - 2\\=22\\DE = DS+SE\\= 22+22\\=44$

Question No 24:

Given

DS = x+3

DE = 56

We know that:

$DS = \frac{1}{2}DE\\x+3 = \frac{56}{2}\\x + 3 = 28\\x = 28-3\\x = 25$

DS = $25+3 = 28$

As DS is 28, SE will also be 28

Hence,

Question 23:

x = 4

DE = 44

Question 24:

x = 25

SE = 28

Keywords: Bisector, Line segment

Learn more about line segments at:

#LearnwithBrainly

4 0

3 years ago