Given:
The volume of a cube-shaped box is
cubic meter.
To find:
The perimeter of each of its faces.
Solution:
Let "a" be the side length of the cube shaped box. Then the volume of the box is:
![V=(side)^3](https://tex.z-dn.net/?f=V%3D%28side%29%5E3)
![V=a^3](https://tex.z-dn.net/?f=V%3Da%5E3)
It is given that the volume of a cube-shaped box is
cubic meter.
![a^3=\dfrac{1}{8}](https://tex.z-dn.net/?f=a%5E3%3D%5Cdfrac%7B1%7D%7B8%7D)
Taking cube root on both sides, we get
![a=\dfrac{1}{2}](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7B1%7D%7B2%7D)
Now, the perimeter of each face of a cube is:
![P=4a](https://tex.z-dn.net/?f=P%3D4a)
Where, a is the side length of the cube.
Putting
, we get
![P=4\times \dfrac{1}{2}](https://tex.z-dn.net/?f=P%3D4%5Ctimes%20%5Cdfrac%7B1%7D%7B2%7D)
![P=2](https://tex.z-dn.net/?f=P%3D2)
Therefore, the perimeter of each face of a cube-shaped box is 2 meters.
Answer:
Step-by-step explanation:
slope of line through (6,-1) and (11,2) = (-1 - 2)/(6 - 11) = 3/5
slope of line through (5,-7) and (8,-2) = (-7 - (-2))/(8 - 5) = -5/3
product of the slopes = -1, so the lines are perpendicular.
Answer:
10.7cm
Step-by-step explanation:
x^2= 115
x = √115
x = 10.7
The behavior of f(x) from given options is option (4) up on the left, up on the right.
<h3>
What is the behavior of function: </h3>
A function f(x) 's end behavior is how the graph of the function f(x) behaves as x gets closer to positive or negative infinity. The functions degree or the polynomial degree and leading coefficient of a given function will determine the end behavior of the function.
Here we have
f(x) = 3x³² + 8x² - 22x + 43
Here
polynomial degree of f(x) is 32
And leading coefficient is 3
Therefore,
The leading term of the given function is 3x³²
As the given polynomial has an even degree (32) and positive leading coefficient (3) then the graph will open upwards on both left and right.
Therefore,
The behavior of f(x) from given options is option (4) up on the left, up on the right.
Learn more about the End behavior of the function at
brainly.com/question/18076811
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