Find the perimeter of the triangle.

Mathematics

1 answer:

Rudiy273 years ago

8 0

Answer:

12 + 10 + 15,62= 37,62

Step-by-step explanation:

According to the Pythagorean Theorem, you will have this:

${a}^{2} + {b}^{2} = {c}^{2} \\ \\ {10}^{2} + {12}^{2} = {c}^{2} \\ \\ 244 = {c}^{2} \\ \\ 2\sqrt{61} = c \\ \\ 15,62049935 ≈ c \\ \\ 15,62 ≈ c \\ \\ 12 + 10 + 15,62 = 37,62$

* There was an error in the correct answer, so I corrected it, as you can see.

I am joyous to assist you anytime.

You might be interested in

would someone be able to explain to me how to solve these problems? I don't need the solutions, I just need an explanation. I ne

Leni [432]

The first 3 are examples of the difference of 2 squares so you use the identity
a^2 - b^2 = (a + b)(a - b)
x^2 - 49 = 0
so (x + 7)(x - 7) = 0
so either x + 7 = 0 or x - 7 = 0
giving x = -7 and 7.
Number 7 reduces to 3x^2 =12, x^2 = 4 so x = +/- 2
Number 8 take out GCf (d) to give
d(d - 2) = 0 so d = 0 , 2
9 and 10 are more difficult to factor
you use the 'ac' method Google it to get more details
2x^2 - 5x + 2
multiply first coefficient by the constant at the end
that is 2 * 2 = 4
Now we want 2 numbers which when multiplied give + 4 and when added give - 5:- -1 and -4 seem promising so we write the equation as:-

2x^2 - 4x - x + 2 = 0

now factor by grouping
2x(x - 2) - 1(x - 2) = 0

(x - 2) is common so

(2x - 1)(x - 2) = 0
and 2x - 1 = 0 or x - 2 = 0 and now you can find x.

The last example is solved in the same way.

8 0

3 years ago

71 to the nearest tenth

xeze [42]

Answer:

ft76d956

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

In fraction form, what is 3/5÷1/3?<br><br>Thank you if answered

sineoko [7]

9/5 is in fraction form

6 0

3 years ago

Read 2 more answers

What is the equation 12= x+ 3

IgorC [24]

X=12 because you would sub the 3 on both sides

3 0

3 years ago

The table below gives data from a linear function. find a formula for the function.

baherus [9]

Given the following table that gives data from a linear function:

$\begin {tabular}
{|c|c|c|c|}
Temperature, $y = f(x)$ (^\circ C)&0&5&20 \\ [1ex]
Temperature, $x$ (^\circ F)&32&41&68 \\ 
\end {tabular}$

The formular for the function can be obtained by choosing two points from the table and using the formular for the equation of a straight line.

Recall that the equation of a straight line is given by
$\frac{y-y_1}{x-x_1} = \frac{y_2-y_1}{x_2-x_1}$

Using the points (32, 0) and (41, 5), we have:
$\frac{y-0}{x-32} = \frac{5-0}{41-32}= \frac{5}{9} \\ \\ \Rightarrow y=\frac{5}{9}(x-32)$

4 0

2 years ago