Answer:
What is the length of an arc cut off?
If θ (in radians) is a central angle in a circle with radius r, then the length of the arc cut off by θ is given by s = r θ (θ is in radians).
Step-by-step explanation:
Length of an Arc = θ × r, where θ is in radian.
Length of an Arc = θ × (π/180) × r, where θ is in degree.
In y = mx + b form, the slope is in the m position and the y int is in the b position.
y = mx + b
slope(m) = -4
y int (b) = -5
y = -4x - 5
or
f(x) = -4x - 5
Answer:
They have the same y-intercept.
Step-by-step explanation:
You can see by the graph that both equations go past the same point in the y-axis. So, you can conclude that they have the same y-intercept. They should not have the same slope because from common sense the slope of the blue line is negative and the slope of the yellow line is positive. They both do not go cross the same point at the x-axis. So, in conclusion both the lines only share the same y-intercept.
Answer:
Step-by-step explanation:
Area of unshaded sector
![= \frac{(360 - 167 )\degree}{360 \degree} \times \pi {r}^{2} \\ \\ 17.8= \frac{197\degree}{360 \degree} \times \pi{r}^{2} \\ \\ \pi{r}^{2} = \frac{17.8 \times 360}{197} \\ \\ \pi{r}^{2} = \frac{6408}{197} \\ \\ \pi{r}^{2} = 32.5279188 \\ \implies \\Area\: of \: circle= 32.5279188\: yd^2 \\\\ Area \: of \: shaded \: sector \\ \\ = 32.5279188 - 17.8 \\ \\ = 14.7279188 \\ \\ \approx 14.7 \: {yd}^{2}](https://tex.z-dn.net/?f=%20%3D%20%20%5Cfrac%7B%28360%20-%20167%20%29%5Cdegree%7D%7B360%20%5Cdegree%7D%20%20%5Ctimes%20%5Cpi%20%7Br%7D%5E%7B2%7D%20%20%5C%5C%20%20%5C%5C%20%2017.8%3D%20%20%5Cfrac%7B197%5Cdegree%7D%7B360%20%5Cdegree%7D%20%20%5Ctimes%20%5Cpi%7Br%7D%5E%7B2%7D%20%20%5C%5C%20%20%5C%5C%20%5Cpi%7Br%7D%5E%7B2%7D%20%20%3D%20%20%5Cfrac%7B17.8%20%5Ctimes%20360%7D%7B197%7D%20%20%5C%5C%20%20%5C%5C%20%5Cpi%7Br%7D%5E%7B2%7D%20%20%3D%20%20%5Cfrac%7B6408%7D%7B197%7D%20%20%5C%5C%20%20%5C%5C%20%20%5Cpi%7Br%7D%5E%7B2%7D%20%20%3D%2032.5279188%20%5C%5C%20%20%5Cimplies%20%5C%5CArea%5C%3A%20of%20%5C%3A%20circle%3D%2032.5279188%5C%3A%20yd%5E2%20%5C%5C%5C%5C%20Area%20%5C%3A%20of%20%5C%3A%20shaded%20%5C%3A%20sector%20%5C%5C%20%20%5C%5C%20%20%3D%2032.5279188%20-%2017.8%20%5C%5C%20%20%5C%5C%20%20%3D%2014.7279188%20%5C%5C%20%20%5C%5C%20%20%5Capprox%2014.7%20%5C%3A%20%20%7Byd%7D%5E%7B2%7D%20)
Imaginary numbers are taught in high school algebra, which I think imaginary numbers are taught in 10th or 11th grade.