Answer:
2^24 = 16,777,216 bacterias.
Step-by-step explanation:
So we start with 1 bacteria
after 1 hours: 2*1 = 2
after 2 hours: 2*2 = 2^2 = 4
after 3 hours: 2*2^2 = 2^3
after n hours: 2^n
Since one day has 24 hours we have n = 24 and total number of bacteria will
be: 2^24 = 16,777,216 bacterias.
Answer:
X=10, x=4
Step-by-step explanation:
first, divide 14 by 2, and square it; giving you
x^2-14x+(7)^2=-40
Because 7^2 is 49, you have to add 49 to the other side; giving you
x^2-14x+(7)^2=9
Then factor the left side; giving you (x-7)^2=9
Take the square root of both sides, giving you
(x-7)^2= plus or minus 3
Then solve to get two solutions, 10 and 4
Answer:
Step-by-step explanation:
Let 
. We have that 
if and only if we can find scalars 
such that 
. This can be translated to the following equations:
1. 
2.
3. 
Which is a system of 3 equations a 2 variables. We can take two of this equations, find the solutions for 
and check if the third equationd is fulfilled.
Case (2,6,6)
Using equations 1 and 2 we get
whose unique solutions are 
, but note that for this values, the third equation doesn't hold (3+2 = 5 
6). So this vector is not in the generated space of u and v.
Case (-9,-2,5)
Using equations 1 and 2 we get
whose unique solutions are 
. Note that in this case, the third equation holds, since 3(3)+2(-2)=5. So this vector is in the generated space of u and v.
Remember, in mathematics, a coefficient is a numerical or constant quantity placed before and multiplying the variable in an algebraic expression.
So, the coefficient in 6-4x-8+2 would be -4.
The domain and range of the given function are equal to (0, 3.85) and (0, 18.75) respectively.
<h3>How to calculate the domain of the function?</h3>
In this exercise, you're given the following function h(t) = -4.87t² + 18.75t. Next, we would equate the function to zero (0) to determine its domain as follows:
0= -4.87t² + 18.75t.
4.87t(-t + 3.85) = 0
t = 0 or t = 3.85.
Therefore, the domain is 0 ≤ t ≤ 3.85 or (0, 3.85).
<h3>How to calculate the range of the function?</h3>
h(t) = -4.87t² + 18.75t
h(t) = -4.87(t² - 3.85t + 3.85 - 3.85)
h(t) = -4.87(t - 1.925)² + 18.05
Therefore, the range is 0 ≤ h ≤ 18.05 or (0, 18.75).
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