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EastWind [94]
3 years ago
5

(◞ ‸ ◟) PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP ≧﹏≦

Mathematics
1 answer:
Natasha_Volkova [10]3 years ago
3 0

6. Classify the angle as acute, right, obtuse, or straight.

A. obtuse

B. acute

C. straight

D. right​

(THE ANSWER IS OBTUSE ANGLE)

An Obtuse Angle Is what your looking at right now. Its angle is bigger than 90 degree.

A Acute angle is lower than 90 degree which tends to make something looking like the “<” “>” sign.

And straight angle is just a straight line (No kidding)

A right angle is justs a L shape sign. The corner of the L 90 degree

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Does the table below represent a proportional relationship?
Ad libitum [116K]

Answer:

C

Step-by-step explanation:

Here, we want to know if the table represents a proportional relationship

Looking at the table, if we multiply the x-terms by -4, we get the y-terms

So the answer here is that Yes, because all the ratios of y to x are equal to -4

6 0
3 years ago
Javier had $1.30. He wants to split the money between himself and nine friends. Which equation shows how he could divide the mon
Reil [10]
B because it u and 9 friends each want the same amount from splitting 1.30 which gives you .13
3 0
3 years ago
Read 2 more answers
How many natural numbers N have the property among 1,2,..........,N exactly 30% are divisible by 3?
k0ka [10]

Answer:

The answer is B. 2.

Step-by-step explanation:

We know that for N = 1 and N = 2, none of them are divisible by 3.

For N = 3, 33.33% are divisible by 3.  For N = 4, 25% (which is already less than 30%), so N = 5 would also be less.

At N = 6, we're back up to 33.33%.  N = 7 is already less than 30%.

At N = 9, you guessed it, 33.33%.  N = 10 is 30% (3, 6, and 9).  So we have one case.

Moving along, at N = 18, 33.33%.  N = 20 is again 30% (3, 6, 9, 12, 15, and 18).  Two cases now.

Finally, at N = 21, again 33.33%.  N = 22 and N = 23 are both greater than 30%.  As we continue this, for any N after 20, we will always be greater than 30%.

4 0
3 years ago
A rectangle has an area of 102 cm2. The length of the rectangle is 17 cm.
densk [106]
102 / 17 = 6 
6 is the width of the rectangle 
17 x 2 + 6 x 2 = the perimeter
34 + 12 = 46  p=46 
6 0
3 years ago
A random sample of 20 students yielded a mean of ¯x = 72 and a variance of s2 = 16 for scores on a college placement test in mat
Helen [10]

Answer:

The 98% confidence interval for the variance in the pounds of impurities would be 8.400 \leq \sigma^2 \leq 39.827.

Step-by-step explanation:

1) Data given and notation

s^2 =16 represent the sample variance

s=4 represent the sample standard deviation

\bar x represent the sample mean

n=20 the sample size

Confidence=98% or 0.98

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi square distribution is the distribution of the sum of squared standard normal deviates .

2) Calculating the confidence interval

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

On this case the sample variance is given and for the sample deviation is just the square root of the sample variance.

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

df=n-1=20-1=19

Since the Confidence is 0.98 or 98%, the value of \alpha=0.02 and \alpha/2 =0.01, and we can use excel, a calculator or a table to find the critical values.  

The excel commands would be: "=CHISQ.INV(0.01,19)" "=CHISQ.INV(0.99,19)". so for this case the critical values are:

\chi^2_{\alpha/2}=36.191

\chi^2_{1- \alpha/2}=7.633

And replacing into the formula for the interval we got:

\frac{(19)(16)}{36.191} \leq \sigma^2 \leq \frac{(19)(16)}{7.633}

8.400 \leq \sigma^2 \leq 39.827

So the 98% confidence interval for the variance in the pounds of impurities would be 8.400 \leq \sigma^2 \leq 39.827.

7 0
3 years ago
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