If you were 2 years old in 2011 how old would you be in 2020?

Mathematics

2 answers:

Roman55 [17]3 years ago

4 0

Answer:

11 years

Step-by-step explanation:

2 years that you were in 2011

2020-2011= 9

2+9=11

also meaning they were born in 2009

2020-2009 also equals 11

this prolly doesnt make sense but hope it helps :) <3

Anna007 [38]3 years ago

4 0

Answer:

Step-by-step explanation:

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How should I do this question

Ivanshal [37]

Answer:

( 11 -6)

( -5 6 )

Step-by-step explanation:

Multiply the first row of N by first column of M. This will give the first element in top row of the answer :-

-3*-2 + 1*5 = 11

Then multiply the first row in N by the second column of M to give the second element of the top row.

-3*0 + 1*-6 = -6

Then do a similar process with the second row in N.

8 0

3 years ago

Read 2 more answers

The point (1, −1) is on the terminal side of angle θ, in standard position. What are the values of sine, cosine, and tangent of

Lilit [14]

Check the picture below.

$\bf (\stackrel{a}{1}~,~\stackrel{b}{-1})\qquad \impliedby \textit{let's find the hypotenuse} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c = \sqrt{a^2+b^2} \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ c=\sqrt{1^2+(-1)^2}\implies c=\sqrt{2} \\\\[-0.35em] ~\dotfill$

$\bf sin(\theta ) \implies \cfrac{\stackrel{opposite}{-1}}{\stackrel{hypotenuse}{\sqrt{2}}}\implies \cfrac{-1}{\sqrt{2}}\cdot \cfrac{\sqrt{2}}{\sqrt{2}}\implies -\cfrac{\sqrt{2}}{(\sqrt{2})^2}\implies -\cfrac{\sqrt{2}}{2}$

$\bf cos(\theta ) \implies \cfrac{\stackrel{adjacent}{1}}{\stackrel{hypotenuse}{\sqrt{2}}}\implies \cfrac{1}{\sqrt{2}}\cdot \cfrac{\sqrt{2}}{\sqrt{2}}\implies \cfrac{\sqrt{2}}{(\sqrt{2})^2}\implies \cfrac{\sqrt{2}}{2} \\\\\\ tan(\theta ) = \cfrac{\stackrel{opposite}{-1}}{\stackrel{adjacent}{1}}\implies tan(\theta ) = -1$