Solve -10.2+173.2xe^(-(10x)/(13))=52

John ran 6 2/3 miles last week he ran 1 1/3 miles each day how many days did he run

Murljashka [212]

$6\frac{2}{3} = \frac{3(6) + 2}{3} = \frac{20}{3} miles$

$1\frac{1}{3} = \frac{3(1) + 1}{3} = \frac{4}{3} miles/day$

$\frac{20}{3} miles$ ÷ $\frac{4}{3} miles/day$

= $\frac{20(miles)}{3}$ * $\frac{3(days)}{4 (miles)}$

= $\frac{20(3) days}{3(4)} = \frac{20 days}{4} = 5 days$

Answer: 5 days

4 0

3 years ago

Miriam is picking out some movies to rent, and she is primarily interested in comedies and foreign films. She has narrowed down

Keith_Richards [23]

Answer:

There are 795 combinations.

Step-by-step explanation:

The number of ways or combinations in which we can select k element from a group of n elements is given by:

$nCk=\frac{n!}{k!(n-k)!}$

So, if Miriam want to choose 3 movies with at least two comedies, she have two options: Choose 2 comedies and 1 foreign film or choose 3 comedies.

Then, the number of combinations for every case are:

1. Choose 2 Comedies from the 10 and choose 1 foreign film from 15. This is calculated as:

$10C2*15C1=\frac{10!}{2!(10-8)!}*\frac{15}{1!(15-14)!}$

$10C2*15C1=675$

2. Choose 3 Comedies from the 10. This is calculated as:

$10C3=\frac{10!}{3!(10-3)!}=120$

Therefore, there are 795 combinations and it is calculated as:

675 + 120 = 795

8 0

3 years ago

Triangle ABL is an isosceles triangle in circle A with a radius of 11, PL = 16, and ∠PAL = 93°. Find the area of the circle encl

katovenus [111]

Answer:

The area of the circle enclosed by line PL and arc PL is approximately 37.62 square units

Step-by-step explanation:

The given parameters in the question are;

The radius of the circle, r = 11

The length of the chord PL = 16

The measure of angle ∠PAL = 93°

The segment of the circle for which the area is required = Minor segment PL

The shaded area of the given circle is the minor segment of the circle enclosed by line PL and arc PL

The area of a segment of a circle is given by the following formula;

Area of segment = Area of the sector - Area of the triangle

In detail, we have;

Area of segment = Area of the sector of the circle that contains the segment) - (Area of the isosceles triangle in the sector)

Area of a sector = (θ/360)×π·r²

Where;

r = The radius of the circle

θ = The angle of the sector of the circle

Plugging in the the values of <em>r</em> and <em>θ</em>, we get;

The area of the sector enclosed by arc PL and radii AP and AL = (93°/360°) × π × 11² ≈ 98.2 square units

Area of a triangle = (1/2) × Base length × Height

Therefore;

The area of ΔAPL = (1/2) × 16 × 11 × cos(93°/2) ≈ 60.58 square units

∴ The area of the segment PL ≈ (98.2 - 60.58) square units = 37.62 square units

Therefore, the area of the shaded segment PL ≈ 37.62 square units

More examples on area of a shaded segment can be found here:

brainly.com/question/22599425

8 0

2 years ago

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Due very soon! Please help

RUDIKE [14]

Answer: y=-5/4x+7

Step-by-step explanation: You can see, by looking at the graph, that the slope will be negative, so you can eliminate the options with a positive slope. You can take the first point (0,7) and the second point (4,2) and calculate the slope (the change in y divided by the change in x). 7-2 is five, so that gives us our numerator of the slope. 0-4 is -4, so that gives us our denominator. That gives us a slope of -5/4, so the only answer with that slope is the third option, y=-5/4+7. I hope this helps!

6 0

3 years ago

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6x10 to the 2 power + 45

trasher [3.6K]

Answer:

the answer is 60045

Step-by-step explanation:

the answer is 60000 because 6×10=60×100=60000+45=60045

4 0

3 years ago

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