A pure substance that cannot be broken into simpler substances by physical or chemical means

References Use the References to access important values if needed for this question A student ran the following reaction in the

ANTONII [103]

Answer:

19.27

Explanation:

Some values are corrected from correct source.Thus,

Moles of SO₂ = 8.19x10⁻² moles

Moles of O₂ = 8.10x10⁻² moles

Volume = 1 L

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

Concentration of SO₂ = 8.19x10² M

Concentration of O₂ = 8.10x10 M

Considering the ICE table for the equilibrium as:

2SO₂ (g) + O₂ (g) ⇔ 2SO₃ (g)

t = o 8.19x10⁻² 8.19x10⁻²

t = eq -2x -x 2x

--------------------------------------------- --------------------------

neq: 8.19x10⁻² -2x 8.19x10⁻² -x 2x

Given:

Equilibrium concentration of O₂ = 5.98x10⁻² M = 8.19x10⁻² -x

Thus, x = 0.0212 M

[SO₂] = 8.19x10⁻² - 2*0.0212 = 0.0395 M

[SO₃] = 2*0.0212 = 0.0424 M

The expression for the equilibrium constant is:

$K_c=\frac {[SO_3]^2}{[SO_2]^2[O_2]}$

$K_c=\frac{{0.0424}^2}{{0.0395}^2\times 0.0598}$

K = 19.27

4 0

3 years ago

Na2O +<br> H20<br> NaOH<br> yeah

kodGreya [7K]

Answer:

<h3>explanation:</h3>

Sodium oxide react with water to produce sodium hydroxide.

8 0

3 years ago

Read 2 more answers

The temperature at the surface of the Sun is approximately 5,150 K, and the temperature at the surface of the Earth is approxima

dezoksy [38]

Answer:

ΔS = 16.569 J/K

Explanation:

In this case, we need to use the correct expression to solve this. In thermodynamics, the expression to use that puts a relation between heat, temperature and entropy is the following:

ΔS = Q/T

To determine the entropy change of the universe, we need to sum the entropy change of Earth and the entropy of the sun.

As the sun is transfering radiation to Earth, the sun is losing energy, therefore, heat is negative, while Earth receives the heat, so it's positive. Calculating the entropy for the sun and Earth:

ΔSs = -Q/Ts

ΔSe = Q/Te

ΔSu = ΔSe + ΔSs

Let's calculate both entropies by separate:

ΔSe = 5x10^3 / 285 = 17.54 J/K

ΔSs = -5x10^3 / 5,150 = -0.971 J/K

Therefore, the entropy of universe:

ΔSu = 17.54 - 0.971

ΔSu = 16.569 J/K

6 0

3 years ago

Draw a structural formula of an alkene or alkenes (if more than one) that undergo acid-catalyzed hydration and without rearrange

AfilCa [17]

Below is the drawing of structural formula of alkenes that undergo acid-catalyzed hydration without rearrangement

3 0

3 years ago

Dead space is the portion of the respiratory system that: Select one: A.. must be filled with air before gas exchange can take p

ololo11 [35]

Answer: Option B

Explanation:

Dead space is the volume of sir in the body which is inhaled but it does not takes part in the gaseous exchange this is because it does not contains alveoli.

Not all the air that is inhaled inside the body is used in the process of respiration.

The dead space in the lungs is the region which helps in conducting airways, the air is not perfused to the alveoli.

5 0

3 years ago