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goldenfox [79]
3 years ago
13

The chemical compound, "AB" has a molar mass of 74.548 g/mol.

Chemistry
1 answer:
sladkih [1.3K]3 years ago
4 0

Answer:

47.55%

Explanation:

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Write the electronic configuration of aluminium in terms of sub shell ​
butalik [34]

Answer:

The Aluminium electron configuration will be 1s^22s^22p^63s^23p^1. The configuration notation provides an easy way for scientists to write and communicate how electrons are arranged around the nucleus of an atom. This makes it easier to understand and predict how atoms will interact to form chemical bonds.

3 0
2 years ago
A break in the earth's surface between two blocks of rock that have moved past each other is called -a fault -a gauge -a plateau
devlian [24]
Correct you know your stuff
5 0
3 years ago
...............................................<br> .
Sergio [31]

Answer:

yuh

Explanation:

5 0
3 years ago
A sample of gas in a closed container at a temperature of 100oC and 3 atm is heated to 300oC. What is the pressure of the gas at
Goshia [24]

Answer:

6.14 atm

Explanation:

Initial temperature (T₁) = 100 °C

Initial pressure (P₁) = 4 atm

Final temperature (T₂) = 300 °C

Final pressure (P₂) =?

NOTE: Volume = constant (since the system is a closed system)

Next, we shall convert celsius temperature to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

Initial temperature (T₁) = 100 °C

Initial temperature (T₁) = 100 °C + 273 = 373 K

Final temperature (T₂) = 300 °C

Final temperature (T₂) = 300 °C + 273 = 573 K

Finally, we shall determine the pressure at the highest temperature as follow:

Initial temperature (T₁) = 373 K

Initial pressure (P₁) = 4 atm

Final temperature (T₂) = 573 K

Final pressure (P₂) =?

P₁ / T₁ = P₂ / T₂

4 / 373 = P₂ / 573

Cross multiply

373 × P₂ = 4 × 573

373 × P₂ = 2292

Divide both side by 373

P₂ = 2292 / 373

P₂ = 6.14 atm

Thus, the pressure at the highest temperature is 6.14 atm

6 0
3 years ago
A 49.3 sample of CaCO3 was treated with aqueous H2SO4, producing calcium sulfate, 3.65 g of water and CO2(g). What was the % yie
yaroslaw [1]

Answer:

41.1%

Explanation:

First write the balanced reaction:

CaCO₃ + H₂SO₄ → CaSO₄ + H₂O + CO₂

Now calculate the theoretical yield:

49.3 g CaCO₃ × (1 mol CaCO₃ / 100 g CaCO₃) = 0.493 mol CaCO₃

0.493 mol CaCO₃ × (1 mol H₂O / 1 mol CaCO₃) = 0.493 mol H₂O

0.493 mol H₂O × (18 g H₂O / mol H₂O) = 8.87 g H₂O

Now calculate the % yield:

3.65 g H₂O / 8.87 g H₂O × 100% = 41.1%

5 0
3 years ago
Read 2 more answers
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