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AnnZ [28]
3 years ago
14

An automobile manufacturer is concerned about a possible recall of its best-selling four-door sedan. If there were a recall, the

re is a probability of 0.25 of a defect in the brake system, 0.18 of a defect in the transmission, 0.17 of a defect in the fuel system, and 0.40 of a defect in some other area. (a) What is the probability that the defect is the brakes or the fueling system if the probability of defects in both systems simultaneously is 0.15?
Mathematics
1 answer:
andrew11 [14]3 years ago
8 0

Answer:

0.27

Step-by-step explanation:

Suppose A is the event of defect in the brake system and B is the event of defect in the fuel system,

We have given,

P(A) = 0.25,

P(B) = 0.17

P(A∩B) = 0.15 ( the probability of defects in both systems simultaneously is 0.15 ),

We know that,

P(A∪B) = P(A) + P(B) - P(A∩B)

= 0.25 + 0.17 - 0.15

= 0.27

Hence, the probability that the defect is the brakes or the fueling system is 0.27.

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The Foley Products Company has designed a new blend of concrete they believe will be twice as strong as their current high quali
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3 years ago
Students voted on a school trip. 56 voted for the museum, 86 for the nature center, 172 for the state capital, and 116 for other
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Answer:

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Step-by-step explanation:

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Determine the number of solutions that exist to the equation?
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6 0
3 years ago
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kvasek [131]

m∠FDE = 52°

Solution:

Given data:

DE ≅ DF, CD || BE, BC || FD and m∠ABF = 116°

<em>Sum of the adjacent angles in a straight line = 180°</em>

m∠ABF + m∠CBF = 180°

116° + m∠CBF = 180°

m∠CBF = 64°

If CD || BE, then CD || BF.

Hence CD || BE and BE || FD.

Therefore BFCD is a parallelogam.

<em>In parallelogram, Adjacent angles form a linear pair.</em>

m∠CBF + m∠BFD = 180°

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m∠BFD = 116°

<em>Sum of the adjacent angles in a straight line = 180°</em>

m∠BFD + m∠DFE = 180°

116° + m∠DFE = 180°

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we know that DE ≅ DF.

<em>In triangle, angles opposite to equal sides are equal.</em>

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m∠FDE = 52°

8 0
3 years ago
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