Answer:
CD = 14 cm; DE = 21 cm
Step-by-step explanation:
The perimeter is the sum of side lengths (in centimeters), so ...
CD + DE + CF + EF = 55
CD + DE + 8 + 12 = 55 . . . . . . . substittute for CF and EF
CD + DE = 35 . . . . . . . . . . . . . . subtract 20
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The segment DF is a diagonal of the rhombus, so bisects angle D. That angle bisector divides ΔCDE into segments that are proportional. That is, ...
CD/DE = CF/EF = 8/12 = 2/3
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So, we have two segments whose sum is 35 (cm) and whose ratio is 2 : 3. The total of "ratio units is 2+3=5, so each must stand for a length unit of 35/5 = 7 (cm). The sides are ...
CD = 2·7 cm = 14 cm
DE = 3·7 cm = 21 cm
<em>Check</em>
CD + DE = (14 +21) cm = 35 cm . . . . . matches requirements
Answer:
No
Step-by-step explanation:
We can check with the Pythagorean Theorem.
a^2 + b^2 = c^2
a and b are always the smaller sides, the legs
c is the longer side, the hypotenuse
3^2 + 3^2 > 6^2
9 + 9 > 36
18 < 36
18 is not greater than 36, therefore this triangle can not have the side lengths 3, 3, and 6.
This the no x value to this problem??
You take y down 5 then add x