Answer: select all what that apply?
Step-by-step explanation:
Based on the elements and charges in Copper (II) Oxalate, CuC₂O₄(s), the solubility in pure water is 1.7 x 10⁻⁴ M.
<h3>What is the solubility of Copper (II) Oxalate in pure water?</h3>
The solubility equilibrium (Ksp) is 2.9 x 10⁻⁸ so the solubility can be found as:
Ksp = [Cu²⁺] [C₂O₄²⁻]
Solving gives:
2.9 x 10⁻⁸ = S x S
S² = 2.9 x 10⁻⁸
S = 1.7 x 10⁻⁴ M
Find out more on solubility at brainly.com/question/23659342.
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Answer:
Step-by-step explanation:
The first term is 2
Therefor t₁ = 2
Each aditional term is 5 times the previous term
That's the second choice
Answer:
-6
Step-by-step explanation:
The notation a23 refers to the element in row 2, column 3. That element is -6.
Answer:
1/2 one half
Step-by-step explanation:
1/2 one half