Trigonometry problem
1 answer:
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<span>The graph is attached.
Explanation:
We can use the x- and y-intercepts to graph. The x-intercept of the first equation is 8, and the y-intercept is 8. The x-intercept of the second equation is -2, and the y-intercept is 2.
<span>
x-intercepts are where the data crosses the x-axis. At every one of these points, the y-coordinate will be 0; therefore we can substitute 0 for y and solve to get the value of the x-intercept.
For the first equation, we would have
8x+8(0)=64
8x=64.
Divide both sides by 8:
8x/8 = 64/8
x=8.
For the second equation,
2x-2(0)=-4
2x=-4.
Divide both sides by 2:
2x/2 = -4/2
x=-2.
y-intercepts are where the data crosses the y-axis. At every one of these points, the x-coordinate will be 0; therefore we can substitute 0 for x and solve to get the value of the y-intercept.
For the first equation,
8(0)+8y=64
8y=64.
Divide both sides by 8:
8y/8 = 64/8
y=8.
For the second equation,
2(0)-2y=-4
-2y=-4.
Divide both sides by -2:
-2y/-2 = -4/-2
y=2.
Plot these points for both equations and connect them to draw the line.</span></span>
Explanation:
We can use the x- and y-intercepts to graph. The x-intercept of the first equation is 8, and the y-intercept is 8. The x-intercept of the second equation is -2, and the y-intercept is 2.
<span>
x-intercepts are where the data crosses the x-axis. At every one of these points, the y-coordinate will be 0; therefore we can substitute 0 for y and solve to get the value of the x-intercept.
For the first equation, we would have
8x+8(0)=64
8x=64.
Divide both sides by 8:
8x/8 = 64/8
x=8.
For the second equation,
2x-2(0)=-4
2x=-4.
Divide both sides by 2:
2x/2 = -4/2
x=-2.
y-intercepts are where the data crosses the y-axis. At every one of these points, the x-coordinate will be 0; therefore we can substitute 0 for x and solve to get the value of the y-intercept.
For the first equation,
8(0)+8y=64
8y=64.
Divide both sides by 8:
8y/8 = 64/8
y=8.
For the second equation,
2(0)-2y=-4
-2y=-4.
Divide both sides by -2:
-2y/-2 = -4/-2
y=2.
Plot these points for both equations and connect them to draw the line.</span></span>