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torisob [31]
4 years ago
10

E. coli and s. epidermidis were chosen to represent gram-negative and gram-positive bacteria, respectively. for a given antibiot

ic, is there a difference in susceptibility between the gram-positive and gram-negative bacteria?
Biology
1 answer:
sammy [17]4 years ago
6 0

Gram-positive and Gram-negative are different in their resistance to antibiotics. It is because of their different structure of cell wall. Gram-positive bacteria have a thick peptidoglycan cell wall and dyes purple in the Gram test (for categorization of bacteria). Gram-negative bacteria have thin peptidoglycan layer and do not turn purple. Gram-positive bacteria are easier to kill because their thick peptidoglycan layer absorbs antibiotics.

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Which of the following vessels delivers lymph into the junction of the internal jugular vein and the subclavian vein?
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In rabbits, short hair is due to a dominant allele, S, and long hair to its recessive allele, s. Black hair is due to a dominant
Natali5045456 [20]

Answer:

SsBB x SsBB

or

SsBB x SsBb

Explanation:

SS- short hair

ss - long hair

BB- black hair

bb- white hair

Total the number of offspring produced = 2518+817=3335

Where 2518= short haired, black offspring SSBB or SsBb

817= Longed Hair, black offspring ssBB or ssBb

To get the offspring proportion for short hair black offspring

2518/3335×100 = 75.5%

long-haired, blackoffspring =817/3335×100 = 25%

This gives ratio of 3:1 as against the proposed dihybrid phenotypic ratio of Mendel experiment 9:3:3:1

Now, if you remember a dihybrid cross results in 9:3:3:1 phentoype ratio. That is when both parents are heterozygous for both alleles. So we can rule that out since it doesn't match our 3:1 ratio.

Since all the offspring are black , it means one parent is homozygous dominant for black and the other parent is either homozygous or heterozygous for the black allele.

Since the ratio is 3:1, for the hair length

That leaves us with the short hair. Since the ratio is 3:1, both parents are heterozygous for hair length.

Therefore, the possible parental genotype is

SsBB x SsBB

or

SsBB x SsBb

4 0
3 years ago
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