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3 years ago

Given that F(x) = x 2 + 2, evaluate F(2). 0 2 6

Mathematics

2 answers:

belka [17]3 years ago

4 0

Answer 6

2^2+2
4+2=6
Got it

Aliun [14]3 years ago

3 0

Answer:

The correct option is C) 6

Step-by-step explanation:

we need to calculate the value of function at x=2

The given function is $F(x)=x^{2}+2$

To calculate F(2), we replace 'x' with 2 in $F(x)=x^{2}+2$

$F(2)=2^{2}+2$

$F(2)=4+2$

$F(2)=6$

Therefore, the correct option is C) 6

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Name: 1. Label the axes. 2. Graph: A(-3, 0) B(-2, 4) C(1, -1) Draw AABC in blue. 3. Rotate AABC 90° clockwise to create AA'B'C'

nikklg [1K]

Answer:

its B because

Step-by-step explanation:

Simplifying

41n(7x) = 8

Remove parenthesis around (7x)

41n * 7x = 8

Reorder the terms for easier multiplication:

41 * 7n * x = 8

Multiply 41 * 7

287n * x = 8

Multiply n * x

287nx = 8

Solving

287nx = 8

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Divide each side by '287x'.

n = 0.02787456446x-1

Simplifying

n = 0.02787456446x-1

3 0

2 years ago

5*45+6856x=8x+65x+76x

Brut [27]

Answer:

0.033547 I think

Step-by-step explanation:

4 0

3 years ago

Given a polynomial f(x), if (x − 4) is a factor, what else must be true?

ollegr [7]

Answer:

$f(4)=0$

Step-by-step explanation:

The Remainder Theorem states that when you divide a polynomial $f(x)$ by a linear factor $(x-a)$ , where $a$ is a constant, the remainder is $f(x)$ evaluated at $x=a$

Moreover, according to the Factor Theorem, an extension of the Remainder Theorem, if the remainder of the function $f(x)$ is 0 when evaluated at $x=a$ , then $(x-a)$ is said to be a factor of the polynomial $f(x)$

Given the 2 theorems above, it follows that if $(x-4)$ is a factor of $f(x)$ , then the remainder is equal to 0 when $f(x)$ is evaluated at $x=4$