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kenny6666 [7]
3 years ago
12

Given that F(x) = x 2 + 2, evaluate F(2). 0 2 6

Mathematics
2 answers:
belka [17]3 years ago
4 0
Answer 6

2^2+2
4+2=6
Got it
Aliun [14]3 years ago
3 0

Answer:

The correct option is <u>C) 6</u>

Step-by-step explanation:

we need to calculate the value of function at x=2

The given function is F(x)=x^{2}+2

To calculate F(2), we replace 'x' with 2 in F(x)=x^{2}+2

F(2)=2^{2}+2

F(2)=4+2

F(2)=6

Therefore, the correct option is <u>C) 6</u>

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2^2 = 4
just think 2 written out TWO times (hence the SECOND power).
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3 years ago
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I need some help with this question, not good at biology
motikmotik

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Biology

the answer is

c . two .

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In this problem we will be dealing with the probability density function (pdf) associated with a continuous random variable, X.
konstantin123 [22]

Answer:

b)\ 0.568

Step-by-step explanation:

Given

f(x) = 6x(1- x);\ 0 \le x \le 1

Required

P(0.3 < x < 0.7)

From the question, we have:

P(a < x < b) = \int\limits^b_a {f(x)} \, dx

So, we have:

P(0.3 < x < 0.7) = \int\limits^{0.7}_{0.3} {6x(1 - x)} \, dx

Open bracket

P(0.3 < x < 0.7) = \int\limits^{0.7}_{0.3} {6x - 6x^2} \, dx

Integrate

P(0.3 < x < 0.7) =  \frac{6x^2}{2} - \frac{6x^3}{3}}|\limits^{0.7}_{0.3}

P(0.3 < x < 0.7) =  3x^2 - 2x^3|\limits^{0.7}_{0.3}

Substitute 0.7 and 0.3 for x

P(0.3 < x < 0.7) =  (3*0.7^2 - 2*0.7^3) - (3*0.3^2 - 2*0.3^3)

Using a calculator, we have:

P(0.3 < x < 0.7) =  (0.784) - (0.216)

Remove brackets

P(0.3 < x < 0.7) =  0.784 - 0.216

P(0.3 < x < 0.7) =  0.568

3 0
2 years ago
This is a similar triangle please find the missing length. (?)
stira [4]

Answer:

10

Step-by-step explanation:

Set up as a proportion:

\frac{QR}{QP}=\frac{BA}{BC}, insert given values

\frac{?}{12}=\frac{30}{36}, cross multiple

36*?=30*12

36*?=360, divide both sides by 36 to get the missing side (?) by itself

?=10

3 0
2 years ago
A shipment of ten smartphones contains five with cracked screens. If sold in a
Natalka [10]

Answer: 73.81%

Step-by-step explanation:

We know that 5 out of 10 have broken screens. So each smartphone has a probability of 50% of having a broken screen.

The probability that at most 3 of them have a broken screen is:

The probability that none has a broken screen p = 0

This is 0 because we are selling six of them and only 5 of them have the screen in good condition.

The probabilities are calculated as:

P = A*6!/(6 - n)!*n!

where n is the number of broken phones.

the probability is equal to

if we have only one broken screen:

for the broken phone, we have a 5/10 probability.

for the other 5 nice phones, the probabilities will be 5/9. 4/8. 3/7, 2/6 and 1/5 (the number changes because when we select one of the phones, the total number of phones decreases)

A = (5*5*4*3*2*1)/(10*9*8*7*6*5)

and is similar thinking for 2 and 3 broken phones.

Probability that one has a broken screen:

  P = ((5*4*3*2*1*5)/(10*9*8*7*6*5))*6 = 0.0238

Probability for two broken screen:

  P = (5*4*3*2*5*4)/(10*9*8*7*6*5))*6*5/2 = 0.2381

For 3 broken phones the probability is:

  P = ((5*4*3*5*4*3)/(10*9*8*7*6*5))*6*5*4/(2*3) = 0.4762

total probability = 0.0238 + 0.2381 + 0.4762 = 0.7381  

or 73.81% in percentage form.

6 0
3 years ago
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