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3 years ago

Given that F(x) = x 2 + 2, evaluate F(2). 0 2 6

Mathematics

2 answers:

belka [17]3 years ago

4 0

Answer 6

2^2+2
4+2=6
Got it

Aliun [14]3 years ago

3 0

Answer:

The correct option is <u>C) 6</u>

Step-by-step explanation:

we need to calculate the value of function at x=2

The given function is $F(x)=x^{2}+2$

To calculate F(2), we replace 'x' with 2 in $F(x)=x^{2}+2$

$F(2)=2^{2}+2$

$F(2)=4+2$

$F(2)=6$

Therefore, the correct option is <u>C) 6</u>

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Answer:

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Step-by-step explanation:

Due to order of operations rules, we must perform the subtraction inside parentheses first, getting:

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3 years ago

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Answer:92,817,765

Step-by-step explanation:Arrange the numbers one on top of the other and line up the place values in columns. The number with the most digits is usually placed on top as the multiplicand.

Starting with the ones digit of the bottom number, the multiplier, multiply it by the last digit in the top number

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When you've multiplied the ones digit by every digit in the top number, move to the tens digit in the bottom number.

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When you finish multiplying, draw another answer line below your last row of answer numbers.

Use long addition to add your number columns from right to left, carrying as you normally do for long addition.

Long Multiplication with Decimals

Long multiplication with decimals using the standard algorithm has a few simple additional rules to follow.

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2 years ago

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What is the square root of 9

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Could the inverse of a non-function be a function? Explain or give an example.

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Answer:

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For example, the inverse of the non-function mapping $\lbrace (0,\, 0),\, (0,\, 1),\, (1,\, 0),\, (1,\, 1) \rbrace\!$ is the same as itself (and thus isn't a function, either.)

Step-by-step explanation:

A mapping is a set of pairs of the form $(a,\, b)$ . The first entry of each pair is the value of the input. The second entry of the pair would be the value of the output.

A mapping is a function if and only if for each possible input value $x$ , at most one of the distinct pairs includes $x\!$ as the value of first entry.

For example, the mapping $\lbrace (0,\, 0),\, (1,\, 0) \rbrace$ is a function. However, the mapping $\lbrace (0,\, 0),\, (1,\, 0),\, (1,\, 1) \rbrace$ isn't a function since more than one of the distinct pairs in this mapping include $1$ as the value of the first entry.

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Consider mapping $\lbrace (0,\, 0),\, (0,\, 1),\, (1,\, 0),\, (1,\, 1) \rbrace\!$ . This mapping isn't a function since the input value $0$ is the first entry of more than one of the pairs.

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$(0,\, 0)$ becomes $(0,\, 0)$ .
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More generally, the inverse of non-trivial ellipses (a class of continuous non-function $\mathbb{R} \to \mathbb{R}$ mappings, including circles) are also non-function mappings.

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