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2 years ago

The distance between a (-5, 3) and b(5, 3) is.

Mathematics

2 answers:

Artemon [7]2 years ago

4 0

The answer you’re looking for is 10

elena-s [515]2 years ago

3 0

Answer:

Distance between A and B is 10 units.

Step-by-step explanation:

Distance between two points (x, y) and (x', y') is represented by

$\sqrt{(x-x')^{2}+(y-y')^{2}}$

and we have to find the distance between points A(-5, 3) and B(5, 3)

So distance AB = $\sqrt{[5-(-5)]^{2}+(3-3)^{2}}$

AB = $\sqrt{(10^{2})}=10$

Therefore distance between two points A and B is 10 units.

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Solve 25^2x+1 = 144

Sergeu [11.5K]

Answer:

X = 0.272

Step-by-step explanation:

Firstly, use a common log on the 25 to undo it. Secondly, use the log25(144) on the other side to get ~ 0.54. Move the 1 over with subtraction and then divide out the 2. This will leave you with X= 0.272

4 0

2 years ago

the first Indianapolis 500 auto race took place in 1911. the winning car covered the 500 miles in 6.7 hours. what was the winnin

Vesna [10]

Average speed = (distance covered) / (time to cover the distance)

   = (500 miles) / (6.7 hours)

   = (500 / 6.7) (mile/hour)

   = 74.63 miles per hour.

I imagine there were quite a number of pit stops included in that.

This is faster than I expected when I first read your question.
That's really gettin' with it for cars in 1911 !

4 0

2 years ago

Which of the following statements is not correct? A every square is a parallelogram B every parallelogram is a rectangle C every

n200080 [17]

A. A square is a special type of parallelogram, so every square is a parallelogram. A. is true.

B. Every parallelogram has two sets of opposite sides parallel, but not all angles are right angles. Only some parallelograms are rectangles, not all. B. is false.

C. A parallelogram with 4 congruent sides is a rhombus. A rhombus is a special type of parallelogram, so every rhombus is a parallelogram. C. is true.

D. A rectangle is a special type of parallelogram, so every rectangle is a parallelogram. D. is true.

7 0

2 years ago

The magnitude and direction of two vectors are shown in the diagram. What is the magnitude of their sum?

VLD [36.1K]

Separate the vectors into their x- and y-components. Let u be the vector on the right and v the vector on the left, so that

u = 4 cos(45°) x + 4 sin(45°) y

v = 2 cos(135°) x + 2 sin(135°) y

where x and y denote the unit vectors in the x and y directions.

Then the sum is

u + v = (4 cos(45°) + 2 cos(135°)) x + (4 sin(45°) + 2 sin(135°)) y

and its magnitude is

||u + v|| = √((4 cos(45°) + 2 cos(135°))² + (4 sin(45°) + 2 sin(135°))²)

… = √(16 cos²(45°) + 16 cos(45°) cos(135°) + 4 cos²(135°) + 16 sin²(45°) + 16 sin(45°) sin(135°) + 4 sin²(135°))

… = √(16 (cos²(45°) + sin²(45°)) + 16 (cos(45°) cos(135°) + sin(45°) sin(135°)) + 4 (cos²(135°) + sin²(135°)))

… = √(16 + 16 cos(135° - 45°) + 4)

… = √(20 + 16 cos(90°))

… = √20 = 2√5

5 0

2 years ago

Read 2 more answers

Is this correct or no

iris [78.8K]

Answer:

Incorrect

Step-by-step explanation:

The correct answer is A.

The slope-intercept form is y-y₁=m(x-x₁)

The problem with B is that if you take out the coordinates for x₁ and y₁, you get the coordinates (1,4). This coordinate does not land on the line.

The coordinates for A is (-1,4). This point does land on the line.

6 0

2 years ago