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Juli2301 [7.4K]
3 years ago
6

B A pair of fair dice is rolled, If the sum of the spots is 7, determine the probability that one di showed a 2.

Mathematics
1 answer:
finlep [7]3 years ago
8 0

Answer:

\text{Probability}=\frac{1}{3}

Step-by-step explanation:

Given : A pair of fair dice is rolled, If the sum of the spots is 7.

To find : Determine the probability that one die showed a 2 ?

Solution :

A pair of fair dice is rolled the outcomes are,

(1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6)

(2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)

(3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6)

(4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)

(5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6)

(6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)

The sum of the spots is 7 i.e. (4,3),(2,5),(5,2),(3,4),(1,6),(6,1).

Total possibility = 6

Favorable outcome is that one die showed a 2 i.e. (2,5),(5,2)= 2

The probability that one die showed a 2 is given by,

\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total outcome}}

\text{Probability}=\frac{2}{6}

\text{Probability}=\frac{1}{3}

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5. Write each comparison as a rate.
stepan [7]

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5, 0.55, 2.00, 3 cm.

Step-by-step explanation:

If you're asking about the unit rates, then..

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4 0
3 years ago
A 100-point test has x questions worth 2 points apiece and y questions worth 4 points apiece. Write an equation in Standard Form
Fofino [41]

Answer:

<h3>2x+2y = 100</h3>

Step-by-step explanation:

Total number of points in the test = 100points

If the test has x questions worth 2 points apiece, then the total number of points for x questions with 2 points each will be 2 * x i.e 2x........  1

Also, if y questions worth 4 points apiece then the total number of points for y questions with 4 points each will be 4 * x i.e 4x ....... 2

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Rearrange

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Hence an equation in Standard Form that would model this situation is 2x+2y = 100

6 0
3 years ago
A box is to be constructed from a sheet of cardboard that is 10 cm by 60 cm by cutting out squares of length x by x from each co
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Volume of a rectangular box = length x width x height<span>

From the problem statement,
length = 60 - 2x
width = 10 - 2x
height = x</span>

<span>
where x is the height of the box or the side of the equal squares from each corner and turning up the sides

V = (60-2x) (10-2x) (x)
V = (60 - 2x) (10x - 2x^2)
V = 600x - 120x^2 -20x^2 + 4x^3
V = 4x^3 - 100x^2 + 600x

To maximize the volume, we differentiate the expression of the volume and equate it to zero.

V = </span>4x^3 - 100x^2 + 600x<span>
dV/dx = 12x^2 - 200x + 600
12x^2 - 200x + 600 = 0</span>

<span>x^2 - 50/3x + 50 = 0

Solving for x,
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So, the answer would be that the maximum volume would be 1056.31 cm^3.
</span><span>
</span>
6 0
3 years ago
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