Ok so here u go
<span>Simplifying
6(2x + -11) + 15 = 21 Reorder the terms:
6(-11 + 2x) + 15 = 21
(-11 * 6 + 2x * 6) + 15 = 21
(-66 + 12x) + 15 = 21 Reorder the terms:
-66 + 15 + 12x = 21 Combine like terms: -66 + 15 = -51
-51 + 12x = 21 Solving
-51 + 12x = 21
Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right.
Add '51' to each side of the equation.
-51 + 51 + 12x = 21 + 51
Combine like terms: -51 + 51 = 0
0 + 12x = 21 + 51
12x = 21 + 51 Combine like terms: 21 + 51 = 72
12x = 72
Divide each side by '12'.
x = 6
Simplifying
x = 6</span>
Answer:
12.8 cm
Step-by-step explanation:
The mnemonic SOH CAH TOA reminds you of the relationships between angles and sides of a right triangle. Here, you have the side opposite the given 70° angle, and you want to find the hypotenuse. The appropriate relation is ...
Sin = Opposite/Hypotenuse
Solving for the hypotenuse, we get ...
Hypotenuse = Opposite/Sin
x = (12 cm)/sin(70°) ≈ 12.77 cm
x ≈ 12.8 cm
Answer:
(a) 0.2061
(b) 0.2514
(c) 0
Step-by-step explanation:
Let <em>X</em> denote the heights of women in the USA.
It is provided that <em>X</em> follows a normal distribution with a mean of 64 inches and a standard deviation of 3 inches.
(a)
Compute the probability that the sample mean is greater than 63 inches as follows:
Thus, the probability that the sample mean is greater than 63 inches is 0.2061.
(b)
Compute the probability that a randomly selected woman is taller than 66 inches as follows:
Thus, the probability that a randomly selected woman is taller than 66 inches is 0.2514.
(c)
Compute the probability that the mean height of a random sample of 100 women is greater than 66 inches as follows:
Thus, the probability that the mean height of a random sample of 100 women is greater than 66 inches is 0.
Assume L=1.5W, where W=width, L= Length of the triangle.
Therefore,
Perimeter (P) = 2(W+L) = 2(W+1.5W) = 2(2.5W) = 5W=20 => W=20/5 = 4 in
Then, L=1.5W = 1.5*4 = 6 in
Area, A= L*W = 6*4 = 24 in^2
The answer to 52245 divided by 215 is 243
