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Drupady [299]
3 years ago
5

Find the length of the third side of a right triangle with a hypotenuse of 17 and a leg of 10.

Mathematics
1 answer:
ddd [48]3 years ago
3 0


You need to use the Pythagorean theorem.
{a}^{2}  +  {b}^{2}  =  {c}^{2}
The hypotenuse is "c" and each leg is either "a" or "b".
{10}^{2}  +  { x}^{2}  =  {17}^{2}
100 +  {x}^{2}  = 289 \\  {x}^{2}  = 189 \\ x = 13.7477270849
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Instructions: Use a graphing calculator to approximate the zeros and vertex of the following quadratic functions. Round to one d
Juli2301 [7.4K]

Using a graphing calculator, we can see the graph of the function y = x²-4x+1:

as we can see, the vertex of the function is (2,-3), and the solutions are (0.3,0) and (3.7,0)

4 0
1 year ago
Plss help me TT
Marina CMI [18]

a. There are 0 or 2 real positive roots for the equation and

b. There are 0 or 2 real negative roots for the equation.

<h3>What is the Descartes'rule of sign?</h3>

Descartes' rule of sign states that

  • The number of real positive zero of a polynomial f(x) is the number of sign changes of the coefficients of f(x) or an even number less than the number of sign changes of the coefficients of f(x)
  • The number of real negative zero of a polynomial f(x) is the number of sign changes of the coefficients of f(-x) or an even number less than the number of sign changes of the coefficients of f(-x)

<h3>How to find the number of possible positive and negative roots are there for the equation?</h3>

Given the equation 0 = −8x¹⁰ − 2x⁷ + 8x⁴ − 4x² − 1, writing it as a polynomial function, we have f(x) = −8x¹⁰ − 2x⁷ + 8x⁴ − 4x² − 1

<h3>a. The number of positive roots</h3>

So, to find the number of positive roots, we find the number of sign changes of the polynomial f(x).

So, f(x) = −8x¹⁰ − 2x⁷ + 8x⁴ − 4x² − 1

Since f(x) has coefficients -8, -2, + 8, -4, -1, there are two sign changes from -2 to + 8 and from + 8 to -4.

So, there are 2 or 2 - 2 = 0 real positive roots.

So, there are 0 or 2 real positive roots for the equation.

<h3>b. The number of negative roots</h3>

So, to find the number of negative roots, we find the number of sign changes of the polynomial f(-x).

So, f(-x) = −8(-x)¹⁰ − 2(-x)⁷ + 8(-x)⁴ − 4(-x)² − 1

= −8x¹⁰ + 2x⁷ + 8x⁴ − 4x² − 1

Since f(x) has coefficients -8, +2, + 8, -4, -1, there are two sign changes from -8 to + 2 and from + 8 to -4.

So, there are 2 or 2 - 2 = 0 real negative roots.

So, there are 0 or 2 real negative roots for the equation.

So,

  • There are 0 or 2 real positive roots for the equation and
  • There are 0 or 2 real negative roots for the equation.

Learn more about Descartes' rule of sign here:

brainly.com/question/28487633

#SPJ1

8 0
2 years ago
What is the error due to using linear interpolation to estimate the value of sinxsin⁡x at x = \pi/3? your answer should have at
Bad White [126]
<h3>Answer:</h3>
  • using y = x, the error is about 0.1812
  • using y = (x -π/4 +1)/√2, the error is about 0.02620
<h3>Step-by-step explanation:</h3>

The actual value of sin(π/3) is (√3)/2 ≈ 0.86602540.

If the sine function is approximated by y=x (no error at x = 0), then the error at x=π/3 is ...

... x -sin(x) @ x=π/3

... π/3 -(√3)/2 ≈ 0.18117215 ≈ 0.1812

You know right away this is a bad approximation, because the approximate value is π/3 ≈ 1.04719755, a value greater than 1. The range of the sine function is [-1, 1] so there will be no values greater than 1.

___

If the sine function is approximated by y=(x+1-π/4)/√2 (no error at x=π/4), then the error at x=π/3 is ...

... (x+1-π/4)/√2 -sin(x) @ x=π/3

... (π/12 +1)/√2 -(√3)/2 ≈ 0.026201500 ≈ 0.02620

6 0
3 years ago
how are using graphs, equations, and tables similar when distinguishing between proportional and nonproportional situations?
svet-max [94.6K]
Because it show the relationship between the x and  y coordinates
6 0
4 years ago
A guitar was originally priced at $90, but Natalie waited to buy it until the guitar was on sale for 5% off. If she paid 4% sale
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Answer:

They paid $89.1 for the guitar.

Step-by-step explanation:

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