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meriva
3 years ago
6

how are using graphs, equations, and tables similar when distinguishing between proportional and nonproportional situations?

Mathematics
1 answer:
svet-max [94.6K]3 years ago
6 0
Because it show the relationship between the x and  y coordinates
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The scale drawing of a rectangular room will be enlarged by a scale factor of 4 to create the actual room. The actual area of th
bearhunter [10]

Answer:

The expression is equal to \frac{150}{4^{2}}

The area of the scale drawing is 9.375\ ft^{2}

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its areas is equal to the scale factor squared

let

z------> the scale factor

x------> the area of the actual room

y-----> the area of the scale drawing

so

z^{2}=\frac{x}{y}

we have

z=4

x=150\ ft^{2}

substitute and solve for y

4^{2}=\frac{150}{y}

y=\frac{150}{4^{2}}=9.375\ ft^{2}

6 0
3 years ago
2x - 3(5 - x) = 35 pls solve
inna [77]

Answer:

x=10

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
In a chemical plant, 24 holding tanks are used for final product storage. Four tanks are selected at random and without replacem
Damm [24]

Answer:

a) P(A) = 0,4607     or   P(A) = 46,07 %

b) P(B) = 0,7120   or 71,2 %

c) P(C) = 0,2055  or P(C) = 20,55 %

Step-by-step explanation:

We will use two concepts in solving this problem.

1.- The probability of an event (A) is for definition:

P(A) = Number of favorable events/ Total number of events FE/TE

2.- If A and B are complementary events ( the sum of them is equal to 1) then:

P(A) = 1 - P(B)

a) The total number of events is:

C ( 24,4) = 24! / 4! ( 24 - 4 )!    ⇒  C ( 24,4) = 24! / 4! * 20!

C ( 24,4) = 24*23*22*21*20! / 4! * 20!  

C ( 24,4) = 24*23*22*21/4*3*2

C ( 24,4) = 24*23*22*21/4*3*2    ⇒  C ( 24,4) =  10626

TE = 10626

Splitting the group of tanks in two 6 with h-v  and 24-6 (18) without h-v

we get that total number of favorable events is the product of:

FE = 6* C ( 18, 3)  = 6 * 18! / 3!*15!  =  18*17*16*15!/15!

FE =  4896

Then P(A) ( 1 tank in the sample contains h-v material is:

P(A) = 4896/10626

P(A) = 0,4607     or   P(A) = 46,07 %

b) P(B) will be the probability of at least 1 tank contains h-v

P(B) = 1 - P ( no one tank with h-v)

Again Total number of events is 10626

The total number of favorable events for the ocurrence of P is C (18,4)

FE = C (18,4) = 18! / 14!*4! = 18*17*16*15*14!/14!*4!

FE = 18*17*16*15/4*3*2  = 3060

Then P = 3060/10626

P = 0,2879

And the probability we are looking for is

P(B) = 1 - 0,2879

P(B) = 0,7120   or 71,2 %

c) We call P(C) the probability of finding exactly 1 tank with h-v and t-i

having 4 with t-i tanks is:

reasoning the same way but now having 4 with t-i (impurities) number of favorable events is:

FE = 6*4* C(14,2) = 24 * 14!/12!*2!

FE = 24* 14*13*12! / 12!*2

FE = 24*14*13/2    ⇒  FE = 2184

And again as the TE = 10626

P(C) = 2184/ 10626

P(C) = 0,2055  or P(C) = 20,55 %

5 0
3 years ago
Determain the equation, in slope intercept form, of the line of the line that has a slope of -6 and passes through the point P(-
Vinil7 [7]

Answer:

<h2>         y = -6x - 16</h2>

Step-by-step explanation:

The point-slope form of the equation is y - y₀ = m(x - x₀), where (x₀, y₀) is any point the line passes through and m is the slope:

m = -6

(-3, 2)    ⇒   x₀ = -3,  y₀ = 2

The point-slope form of the equation:

y - 2 = -6(x + 3)

So:

y - 2 = -6x - 18         {add 2 to both sides}

y = -6x - 16             ←  the slope-intercept form of the equation

5 0
3 years ago
CW 18 118 The following information is given to you: Cost of material per unit : Rs.200 Ordering cost : Rs.100 per order Annual
elena-14-01-66 [18.8K]
Ay yo you got this dude
4 0
3 years ago
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