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3 years ago

how are using graphs, equations, and tables similar when distinguishing between proportional and nonproportional situations?

Mathematics

1 answer:

svet-max [94.6K]3 years ago

6 0

Because it show the relationship between the x and y coordinates

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I need help with this.

Sloan [31]

9514 1404 393

Answer:

61.4

Step-by-step explanation:

The length of two semicircles of diameter 10 is the circumference of a circle of that diameter:

C = πd = 10π ≈ 31.4

The perimeter includes that length plus the lengths of two straight sides that are 15 units each.

P = 31.4 + 2×15

P = 61.4 . . . . units

4 0

2 years ago

42 divided by 4 and 67 divided by8

Bezzdna [24]

10.5 and 8.4 ......................,,,,,

6 0

2 years ago

Read 2 more answers

Please help me find the area of shaded region and step by step

Bumek [7]

Answer:

Part 1) $A=60\ ft^2$

Part 2) $A=80\ cm^2$

Part 3) $A=96\ m^2$

Part 4) $A=144\ cm^2$

Part 5) $A=9\ m^2$

Part 6) $A=(49\pi -33)\ in^2$

Step-by-step explanation:

Part 1) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior rectangle

The area of rectangle is equal to

$A=bh$

where

b is the base of rectangle

h is the height of rectangle

$A=(12)(7)-(8)(3)$

$A=84-24$

$A=60\ ft^2$

Part 2) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior square

The area of square is equal to

$A=b^2$

where

b is the length side of the square

$A=(12)(8)-(4^2)$

$A=96-16$

$A=80\ cm^2$

Part 3) we know that

The area of the shaded region is equal to the area of four rectangles plus the area of one square

$A=4(4)(5)+(4^2)$

$A=80+16$

$A=96\ m^2$

Part 4) we know that

The shaded region is equal to the area of the complete square minus the area of the interior square

$A=(15^2)-(9^2)$

$A=225-81$

$A=144\ cm^2$

Part 5) we know that

The area of the shaded region is equal to the area of triangle minus the area of rectangle

The area of triangle is equal to

$A=\frac{1}{2}(b)(h)$

where

b is the base of triangle

h is the height of triangle

$A=\frac{1}{2}(6)(7)-(6)(2)$

$A=21-12$

$A=9\ m^2$

Part 6) we know that

The area of the shaded region is equal to the area of the circle minus the area of rectangle

The area of the circle is equal to

$A=\pi r^{2}$

where

r is the radius of the circle

$A=\pi (7^2)-(3)(11)$

$A=(49\pi -33)\ in^2$

7 0

3 years ago

WILL MARK BRAINLIEST Triangle KON is dilated with a center at the origin and a

alexdok [17]

The answer is c: 0,6

3 0

2 years ago

Read 2 more answers

A circle has radius 50 cm. Find the area of the circle to the nearest hundredth.

padilas [110]

Multiply by 2 which will get you a diameter and then multiply it by pi which is 3.14.

7 0

2 years ago