Answer:
46 cm
Step-by-step explanation:
Let p represent the length in cm of 1 bap'ai; let k represent the length in cm of 1 bok'ai. Then we have ...
12p +2k = 100
10p +10k = 100
Subtracting the second equation from 5 times the first, we get ...
5(12p +2k) -(10p +10k) = 5(100) -(100)
50p = 400
p = 8 . . . . cm
Then the second equation tells us ...
10(8) +10k = 100
10k = 20
k = 2 . . . . cm
Then 5p+3k = 5(8) +3(2) = 46 cm.
The distance 5 bap'ai and 3 bok'ai is 46 cm.
We need to use Law of sine.
sin A/a = sin C/c
sin A/|CB| = sin C/|AB|
sin A/14 = sin(118⁰)/ 20
sin A = (14*sin(118⁰))/ 20
A=arcsin((14*sin(118⁰))/ 20) ≈ 38⁰
Answer:
193.53 miles
Step-by-step explanation:
Please see the diagram for understanding of how the angles were derived,
Applying Alternate Angles, ABO =77 degrees
The bearing from B to C is 192=180+12 degrees
Subtracting 12 from 77, we obtain the angle at B as 65 degrees.
We want to determine the boat's distance from its starting point.
In the diagram, this is the line AC.
Applying Law of Cosines:
The distance of the boat from its starting point is 193.53 miles (correct to 2 decimal places).
Answer:
D. 2.48 in³.
Step-by-step explanation:
Slope intercept form is y = mx + b where m is slope and b is y intercept.
The line crosses the y axis at y = 4
The slope is 4/3
So the answer is y = (4x/3) + 4
