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Korvikt [17]
3 years ago
13

If ∠C ≅ ∠​M, ∠E ≅ ∠​Q, ≅ , ≅ , and ≅ , then _____ ≅ ∆MQN

Mathematics
1 answer:
sashaice [31]3 years ago
6 0
Then angle MQN is <span>≅  angle MQN</span> 
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lara [203]

Answer:

Graph B

This is because of the vertical line test. Say you were to draw a vertical line that stretches through the whole graph. If this line you draw passes through more than two points of the same line/function/whatever b is, it is not a function.

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2 years ago
Factor the expression below. x2 - 4x + 4 A. 4(x2 - x + 1) B. (x - 2)(x + 2) C. (x + 2)(x + 2) D. (x - 2)(x - 2)
Tanzania [10]

Answer:

D. (x - 2)(x - 2)

Step-by-step explanation:

x2 - 4x + 4 = x² - 2x - 2x +4

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4 0
3 years ago
The parking lot at a store has a width of 20 yards 2 feet and a length of 30 yards
Liula [17]

Answer:

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5 0
3 years ago
Read 2 more answers
Fraction for dividing 4 pies equally between 6 people
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3 0
3 years ago
where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤
marusya05 [52]

THIS IS THE COMPLETE QUESTION BELOW

The demand equation for a product is p=90000/400+3x where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤ 50.

Answer

$168.27

Step by step Explanation

Given p=90000/400+3x

With the limits of 40 to 50

Then we need the integral in the form below to find the average price

1/(g-d)∫ⁿₐf(x)dx

Where n= 40 and a= 50, then if we substitute p and the limits then we integrate

1/(50-40)∫⁵⁰₄₀(90000/400+3x)

1/10∫⁵⁰₄₀(90000/400+3x)

If we perform some factorization we have

90000/(10)(3)∫3dx/(400+3x)

3000[ln400+3x]₄₀⁵⁰

Then let substitute the upper and lower limits we have

3000[ln400+3(50)]-ln[400+3(40]

30000[ln550-ln520]

3000[6.3099×6.254]

3000[0.056]

=168.27

the average price p on the interval 40 ≤ x ≤ 50 is

=$168.27

8 0
3 years ago
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