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Scorpion4ik [409]
3 years ago
9

GUESS AND CHECK

Mathematics
1 answer:
ladessa [460]3 years ago
6 0

Answer:

with 128 legsin in all 56 160 one of them

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The answer is d , 0.25 inches per month
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Answer pls i need help
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What/where is the question you have for me?

Step-by-step explanation:


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Thirty Mercedes and Audi participated in a 30 mile race. The average driving speed of the Mercedes and Audi were recorded. A ran
vladimir1956 [14]

Answer:

Median for sample 1 = 142

Median for sample 2 = 134

Step-by-step explanation:

For Sample 1:

For finding median, the data is first arranged into ascending or descending order. We are arranging the data in ascending order.

120, 130, 132, 136, 139, 142, 142, 144, 156, 165, 167

The formula for calculating the term which will be median is:

Median= ((n+1)/2)

Here in sample 1, n=11

So, putting n=11 in the formula

= ((11+1)/2)

= (12/2)

=6th term

The sixth term is 142, so

Median of sample 1=142

For Sample 2:

For finding median, the data is first arranged into ascending or descending order. We are arranging the data in ascending order.

112, 112, 113, 114, 125, 134, 141, 145, 146, 163, 165

The formula for calculating the term which will be median is:

Median= ((n+1)/2)

Here in sample 2, n=11

So, putting n=11 in the formula

=((11+1)/2)

=(12/2)

=6th term

The sixth term is 134, so

Median of sample 2=134

7 0
3 years ago
Find the equation of the line passing through the points A(3,2) and B(6,3)
icang [17]

Answer:

y = \frac{1}{3} x+1

Step-by-step explanation:

m = m = \frac{change in y}{change in x} \\m = \frac{3 - (2)}{6 - (3)}\\m = \frac{1}{3} \\Find the value of b using the equation of a line \\y = mx+b\\y =( \frac{1}{3} )x + b\\2 =( \frac{1}{3} ) * (3) + b\\cancel common factor\\1 + b = 2\\b = 1\\y = \frac{1}{3} x + 1

5 0
3 years ago
FUNDRAISING A school is raising money by selling calendars for $20 each. Mrs. Hawkins promised a party to whichever of her Engli
____ [38]

Rj, this is the solution to question 19:

• 1st period class sold 60 calendars in total

,

• 2nd period class sold 123 calendars in total

We calculate the average per week, this way:

• 1st period class sold 60/4 = 15 calendars per week

,

• 2nd period class sold 123/4 = 30.75 calendars per week

In consequence the multiplication equation that represents this situation is:

15w + 30.75w = 183, where w is the number of weeks Mrs. Hawkins' classes sold calendars.

This is the solution to question 20:

We already know the average number of calendars that 1st and 2nd period classes sold per week. Now, let's calculate the average for 3nd 4th peiod classes, this way:

• 3rd period class sold 89 calendars in total

,

• 4th period class sold 126 calendars in total

Therefore, the average is:

• 3rd period class sold 89/4 = 22.25 calendars per week

,

• 4th period class sold 126/4 = 31.5 calendars per week

Summarizing, we have:

15 + 30.75 + 22.25 + 31.5 = 99.5 calendars was the average number sold by all her classes in a week.

•

7 0
1 year ago
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