Question

a total eclipse in 2003 lasted 2 17/24,minutes in 2005 it lasted 3/8 of a minute how much longer did it last in 2003

Answer 1

Answer:

$2\frac{1}{3}$ minutes

Step-by-step explanation:

We know that in 2003, a total eclipse lasted for $2\frac{17}{24}$ minutes and in 2005, it lasted for $\frac{3}{8}$ minutes.

To find out how much longer did the total eclipse last in 2003, we simply need to find the difference between the duration of two eclipses.

= $2\frac{17}{24}$ - $\frac{3}{8}$

= $\frac{65}{24}$ - $\frac{3}{8}$

= $\frac{65-9}{24}$

= $2\frac{1}{3}$

So it lasted $2\frac{1}{3}$ minutes longer in 2003.

Answer 2

Answer:

Total eclipse was $2\frac{1}{3}$ minutes longer than in 2005.

Step-by-step explanation:

It is given in the question that total eclipse in 2003 lasted $2\frac{17}{24}$ minutes and in 2005 it lasted 3/8 of a minute.

We have to calculate how much longer did it last in 2003.

So we have to subtract the duration in 2003 by duration in 2005

Total time taken in 2003- total time taken in 2005

$=2\frac{17}{24}-\frac{3}{8}$

$\frac{48+17}{24}-\frac{3}{8}$

$=\frac{65}{24}-\frac{3}{8}$

$=\frac{65-9}{24}$

$=\frac{56}{24}$

$\frac{7}{3}$

$=2\frac{1}{3}$ minutes