1] Given that the value of x has been modeled by f(x)=12500(0.87)^x, then:
the rate of change between years 1 and 5 will be:
rate of change is given by:
[f(b)-f(a)]/(b-a)
thus:
f(1)=12500(0.87)^1=10875
f(5)=12500(0.87)^5=6230.3
rate of change will be:
(6230.3-10875)/(5-1)
=-1161.2
rate of change in years 11 to 15 will be:
f(11)=12500(0.87)^11=2701.6
f(15)=12500(0.87)^15=1,547.74
thus the rate of change will be:
(1547.74-2701.6)/(15-11)
=-288
dividing the two rates of change we get:
-288/-1161.2
-=1/4
comparing the two rate of change we conclude that:
The average rate of change between years 11 and 15 is about 1/4 the rate between years 1 and 5.
The answer is D]
2] Given that the population of beavers decreases exponentially at the rate of 7.5% per year, the monthly rate will be:
monthly rate=(n/12)
where n is the number of months
=7.5/12
=0.625
This is approximately equal to 0.65%. The correct answer is A. 0.65%
Answer:
x =45 and y = 23
Step-by-step explanation:
Answer:
The given expression in simplified form is: 
Step-by-step explanation:
Simplifying the expression involve reducing the number of terms to minimum and making the expressions in standard form.
This may involve addition, subtraction and multiplication of variables.
Given expression is:
Distributing 5x will give us:
Hence,
The given expression in simplified form is:
Answer:
8) scale factor: 3
angles Q & L, S & N, r & M
sides 10 x 3 = 30, 6 x 3 = 18, 13 x 3 = 39
9) scale factor: 0.4
angles B & F, C & G, D & H, A & E
sides 9 x 0.4 = 3.6, 7.5 x 0.4 = 3, 10 x 0.4 = 4, 12 x 0.4 = 4.8
