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3 years ago

James has 858 feet of rope. There are 18 teams of hikers.

Mathematics

1 answer:

soldier1979 [14.2K]3 years ago

6 0

Answer:

48 or 47

Step-by-step explanation:

858/18 = 47.6

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Someone please help me answer this!!

PolarNik [594]

0.000518
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3 years ago

The mean score of 8 players is 14.5. If the highest individual score is removed the mean of the score of the remaining 7 players

AfilCa [17]

Answer:

The highest score is 32.

Step-by-step explanation:

We are given the following in the question:

The mean score of 8 players is 14.5.

Let x denote the highest score.

If x is removed, the mean of the score of the remaining 7 players is 12.

Formula for mean:

$\bar{x} = \dfrac{\displaystyle\sum x_i}{n}$

Putting values, we get:

$14.5 = \dfrac{\displaystyle\sum x_i}{8}\\\\\Rightarrow \displaystyle\sum x_i = 116\\\\12 = \dfrac{\displaystyle\sum y_i}{7}\\\\\Rightarrow \displaystyle\sum y_i = 84\\\\\displaystyle\sum y_i = \displaystyle\sum x_i -x \\\\84 = 116 - x\\\Rightarrow x = 32$

Thus, the highest score is 32.

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3 years ago

a local park is shaped like a square with sides 6 meters long. A circular splash fountain is being placed in the middle of the p

DENIUS [597]

Answer: 624 Square meters

Step-by-step explanation:

6 0

3 years ago

Can somebody help me with these problems please

mario62 [17]

Answer:

11. A. $\frac{12}{13}$

12. D. $\frac{35}{12}$

Step-by-step explanation:

11: Sin is just the side opposite of the angle divided by the hypotenuse of the triangle

Opposite of A = 36

Hypotenuse of the triangle = 39

36/39 = $\frac{12}{13}$

12. Tan is the side opposite of the angle divided by the side adjacent to the angle

Opposite of C = 35

Adjacent to C = 12

35/12 = $\frac{35}{12}$

Hope this helps!

3 0

2 years ago

Plz..... Solve this questions for me...

faust18 [17]

$6.\\\text{We know}\ 9=3^2.\ \text{Therefore}\\\\9^2=(3^2)^2\\\\\text{use}\ (a^n)^m=a^{nm}\\\\9^2=(3^2)^2=3^{2\cdot2}=3^4\\\\\boxed{3^4=9^2}\\=================$

$7.\\METHOD\ 1:\\\\\sqrt{7^4}=\sqrt{7^{2\cdot2}}\\\\\text{use}\ (a^n)^m=a^{nm}\\\\=\sqrt{(7^2)^2}\\\\\text{use}\ \sqrt{a^2}=a\ \text{for}\ a\geq0\\\\=\boxed{7^2}\\\\METHOD\ 2:\\\\\text{use}\ a^\frac{m}{n}=\sqrt[n]{a^m}\\\\\sqrt{7^4}=7^\frac{4}{2}=\boxed{7^2}\\=================$

$8.\\5^a\times5^b=5^{11}\\\\a)\\\text{use}\ a^n\times a^m=a^{n+m}\\\\5^a\times5^b=5^{a+b}\\\\5^{a+b}=5^{11}\Rightarrow a+b=11\\\\11\ \text{is odd. The sum of even and odd is odd. Therefore}\ a\ \text{and}\ b\ \text{can't be even.}\\--------------------\\\\b)\\5\ \text{solutions}\\\\11=5+6\\11=4+7\\11=3+8\\11=2+9\\11=1+10$

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3 years ago