Distance = sqrt (x2 - x1)^2 + (y2 - y1)^2
(0,3).....x1 = 0 and y1 = 3
(4,1)....x2 = 4 and y2 = 1
now we sub and solve
d = sqrt (4 - 0)^2 + 1 - 3)^2
d = sqrt (4^2) + (-2^2)
d = sqrt (16 + 4)
d = sqrt 20
d = 4.472 <==
The equation is s=144t - 16t², s being the distance and V=144 ft/s
a)The maximum (or minimum) is reached when the derivative of s = 0
s' = 144 - 32t = 0 and t= 9/2 or 4.5 second (time needed to reach the max
Now plug t= 4.5 in the original equation and you will find s = 324 ft
(Why it's a max and not a minimum: because 2nd derivative is negative and equals s" = -32)
b) Velocity of the ball: distance (up) s=320 ft, time that means:
320 =144t - 16t² (solve for x) -16t²+144t-320 = 0, t₁ =4 and t₂ =5 (t₂ is not valid since max time to reach summit is 4.5) so t =4s , distance = 320. so the velocity at 320ft is 320/4 = 80 ft/s
c) Due to the symmetry of the parabola, the velocity at 320 ft on its way down = 80 ft/s
Answer:
14 minutes
Step-by-step explanation:
you subtract 22-8 and you get 14
Answer:
Step-by-step explanation:
2x+5=-12
2x=-17
x=-8.5
Answer:
A≈706.86ft²
Step-by-step explanation:
A=πr2=π·152≈706.85835ft²
rounded two decimal places= 706.86
