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shepuryov [24]
2 years ago
11

The table shows a pattern of exponents.

Mathematics
1 answer:
ahrayia [7]2 years ago
7 0

Answer: c. divide the previous value by 5

Step-by-step explanation:

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Write and solve an equation for the total number of possible combinations from flipping a coin 10 times. Please help quick, I'm
Furkat [3]
The total number of possible combinations from flipping a coin 10 times is 2^10 = 1024.
3 0
3 years ago
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13 and 5/8 plus 7/8 please answer quickly
Salsk061 [2.6K]

13 5/8 + 7/8 = 14 1/2

5/8 + 7/8 = 1 4/8 = 1 1/2

1 1/2 + 13 = 14 1/2

8 0
3 years ago
Two types of sandwiches were made for a tea party. 55% of the sandwiches were cheese sandwiches and the rest were chicken sandwi
Helen [10]

"To solve this problem, the formula can be used

I = P / T

Where I is the fraction of the sample

P is the amount of the sample

T is the total amount of sample

Since P = 252 chicken sandwiches and I = 0.55

And solve for T

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hope this helps


7 0
3 years ago
X/3 -9=-12 what is x
Pavel [41]
The answer for x should be X= -9
7 0
3 years ago
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What is the horizontal asymptote for y(t) for the differential equation dy dt equals the product of 2 times y and the quantity 1
marta [7]
First, we need to solve the differential equation.
\frac{d}{dt}\left(y\right)=2y\left(1-\frac{y}{8}\right)
This a separable ODE. We can rewrite it like this:
-\frac{4}{y^2-8y}{dy}=dt
Now we integrate both sides.
\int \:-\frac{4}{y^2-8y}dy=\int \:dt
We get:
\frac{1}{2}\ln \left|\frac{y-4}{4}+1\right|-\frac{1}{2}\ln \left|\frac{y-4}{4}-1\right|=t+c_1
When we solve for y we get our solution:
y=\frac{8e^{c_1+2t}}{e^{c_1+2t}-1}
To find out if we have any horizontal asymptotes we must find the limits as x goes to infinity and minus infinity. 
It is easy to see that when x goes to minus infinity our function goes to zero.
When x goes to plus infinity we have the following:
$$\lim_{x\to\infty} f(x)$$=y=\frac{8e^{c_1+\infty}}{e^{c_1+\infty}-1} = 8
When you are calculating limits like this you always look at the fastest growing function in denominator and numerator and then act like they are constants. 
So our asymptote is at y=8.

3 0
3 years ago
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