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3 years ago

Can you help me find the area of this triangle??

Mathematics

1 answer:

I am Lyosha [343]3 years ago

7 0

A = (1/2)*b*h = (1/2)*8*10 = 40 . . . . units^2

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4x8 i know the anwser im just tryna see something

Umnica [9.8K]

Answer:

Step-by-step explanation:

4 0

3 years ago

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PLEASE HELP! I HAVE TWO QUESTIONS AND WILL GIVE 100PTS AND BRAINLIEST IF CORRECT!

Volgvan

Answer:

1) $283.50

2) 65.21 meters.

Step-by-step explanation:

Part 1)

We know that a spool of ribbon holds 6.75 meters.

A craft club buys 21 spools.

So, the total length of ribbon bought is:

$T=21(6.75)=141.75\text{ meters}$

Each meter costs $2. So, the total cost will be:

$141.75(2)=\$ 283.50$

Part 2)

A spool holds 6.75 meters.

We bought 21 of them, so that total length we have is 141.75 meters.

The club used 76.54 meters.

So, the amount of ribbon that is left is represented by:

$141.75-76.54$

Subtract:

$=65.21\text{ meters}$

So, 65.21 meters of ribbon will be left.

7 0

3 years ago

Read 2 more answers

Need help. greatly appreciated

gizmo_the_mogwai [7]

1. It must be divisible by 2 and 3. It IS divisible by 2. it IS divisible by 3. No remainder.
2. Add the digits and see if the sum is divisible by 3. Apply this rule to both numbers. 3 is not a common factor.
3a. 639
3b. 1035
3c. 179

7 0

3 years ago

A bag contains 70 pencils out of which 15 are green and 30 blue.(i)How many pencils of other colours. are in the bag?(ii)A penci

Bas_tet [7]

Answer:

i) 25

ii) 30:70; 30 out of 70 pencils will be blue.

Step-by-step explanation:

i) 70 - (15+30)= 25 other colors in the bag.

ii) 30:70

4 0

4 years ago

The table show the age in years of employees in a company

adelina 88 [10]

Answer:

A. 24 ≤ a < 26.

B. 22.5

Step-by-step explanation:

A. Determination of the modal class interval.

Mode is the class with the highest frequency.

From the table given above, the highest frequency is 8, therefore the class will the highest frequency is:

24 ≤ a < 26.

B. To obtain the mean, we must determine the class mark. This is illustrated below:

Class >>>>> class mark >>> frequency

18 – 19 >>>> 18.5 >>>>>>>>> 3

20 – 21 >>> 20.5 >>>>>>>> 2

22 – 23 >>> 22.5 >>>>>>>> 7

24 – 25 >>> 24.5 >>>>>>>> 8

26 >>>>>>>> 26 >>>>>>>>> 0

The mean is given by the summation of the product of the class mark and frequency divided by the total frequency. This is illustrated below:

Mean = [(18.5x3) + (20.5x2) + (22.5x7) + (24.5x8) + (26x0)] / (3+2+7+8+0)

Mean = (55.5 + 41 + 157.5 + 196 + 0)/20

Mean = 450/20

Mean = 22.5

Therefore, the mean age is 22.5

4 0

3 years ago

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