<span>
f(x)= −3/5x³</span><span>
The domain is all values x can be. There are no restrictions on x. it can be any real number (-∞ , ∞)
The range is all values y can be. There are noi restrictions on y either because the function is odd. y is </span><span>(-∞ , ∞)
The best answer is D.
domain (-∞, 0] ∪[0, ∞)
range </span><span>(-∞, 0] ∪[0, ∞) </span>
Answer : The length of the wire is, 8533 cm
Step-by-step explanation :
As the iron sphere is beaten and drawn into a wire. That means, their volume will be equal.
Volume of iron sphere = Volume of cylindrical wire
The formula will be:
![\frac{4}{3}\pi r_1^3=\pi r_2^2h](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B3%7D%5Cpi%20r_1%5E3%3D%5Cpi%20r_2%5E2h)
where,
= radius of sphere = ![\frac{Diamtere}{2}=\frac{8cm}{2}=4cm](https://tex.z-dn.net/?f=%5Cfrac%7BDiamtere%7D%7B2%7D%3D%5Cfrac%7B8cm%7D%7B2%7D%3D4cm)
= radius of cylindrical wire = ![\frac{Diamtere}{2}=\frac{2mm}{2}=1mm=0.1cm](https://tex.z-dn.net/?f=%5Cfrac%7BDiamtere%7D%7B2%7D%3D%5Cfrac%7B2mm%7D%7B2%7D%3D1mm%3D0.1cm)
h = height of cylindrical wire or length of wire
Now put all the given values in the above formula, we get:
![\frac{4}{3}\pi r_1^3=\pi r_2^2h](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B3%7D%5Cpi%20r_1%5E3%3D%5Cpi%20r_2%5E2h)
![\frac{4}{3}\times r_1^3=r_2^2h](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B3%7D%5Ctimes%20r_1%5E3%3Dr_2%5E2h)
![\frac{4}{3}\times (4)^3=(0.1)^2h](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B3%7D%5Ctimes%20%284%29%5E3%3D%280.1%29%5E2h)
![h=8533.33cm\approx 8533cm](https://tex.z-dn.net/?f=h%3D8533.33cm%5Capprox%208533cm)
Therefore, the length of the wire is, 8533 cm
Answer:
The perpendicular bisector meets any line at an angle which is not 90°
Step-by-step explanation:
![.](https://tex.z-dn.net/?f=.)
Answer:
10 sqrt 3.
Step-by-step explanation:
sqrt30 = sqrt10 * sqrt 3
so sqrt30 * sqrt10
= sqrt10 * sqrt10 * sqrt3
= 10 sqrt 3.