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baherus [9]
3 years ago
13

Find the direction angle of 3i+j

Mathematics
1 answer:
Marat540 [252]3 years ago
4 0

Answer:

18,435°

Step-by-step explanation:

tan (α) = 1/3

arctan (1/3) = 18,435 degrees

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What is a problem that requires adding one two the quotient
Nikolay [14]

division problem

In a division problem, the number being divided into pieces is the dividend. The number by which the dividend is divided is called the divisor. And the answer to the division problem is the quotient.

6 0
3 years ago
Rachel is mailing packages. Each small package costs her $2.60 to send. Each large package costs her$4.10. How much will it cost
Tresset [83]

Answer:

$7.8

Step-by-step explanation:

$2.6 x 3

= $7.8

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3 years ago
1. Which equation is equivalent to the equation 6x + 9 = 12?
yanalaym [24]

Answer:

B

Step-by-step explanation:

if we divide both sides of 6x + 9 = 12 by 3

(6x + 9)/3 = 12/3

2x + 3 = 4 ---> which matches choice B

4 0
3 years ago
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An ellipse is centered at the origin. Find it’s equation.
MA_775_DIABLO [31]

Answer:

(x)^2        (y)^2

---------- + --------- = 1

 4              3

Step-by-step explanation:

The standard equation for an ellipse is

(x-h)^2     (y-k)^2

---------- + --------- = 1

a^2            b^2

The center is at (h,k)

The vertices are at (h±a, k)

The foci are at (h±c,k )

Where c is sqrt(a^2 - b^2)

It is centered at the origin so h,k are zero

(x)^2        (y)^2

---------- + --------- = 1

a^2            b^2

The center is at (0,0)

The vertices are at (0±a, 0)

The foci are at (0±c,0 )

The vertices are (±2,0)  so a =2

The foci is 1

c = sqrt(a^2 - b^2)

1 = sqrt(2^2 - b^2)

Square each side

1 = 4-b^2

Subtract 4 from each side

1-4 = -b^2

-3 = -b^2

3= b^2

Take the square root

b=sqrt(3)

(x)^2        (y)^2

---------- + --------- = 1

 4              3

4 0
3 years ago
OAB is a sector of a circle <br>what is the area of the sector
oee [108]

Answer:

12.56 square cm

Step-by-step explanation:

Central \:angle \:(\theta) = 40°\\Radius \: (r) = 6 cm

Let A be the area of the sector of circle.

\therefore \: A =  \frac{\theta }{360 \degree}  \times \pi {r}^{2}  \\  \\=  \frac{ 40 \degree}{360 \degree}  \times 3.14\times {6}^{2}  \\  \\    =   \frac{ 1}{9}  \times 3.14 \times  36 \\  \\  =   3.14 \times 4 \\ \\ = 12.56 \:  {cm}^{2}

6 0
3 years ago
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