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Elanso [62]
3 years ago
7

Find two numbers that complete the image below such that the middle two bricks sum to the bottom brick and multiply to the top b

rick.

Mathematics
1 answer:
mamaluj [8]3 years ago
4 0

Answer:

Could it be 14 in the middle brick and 350 in the top brick. Or im just rlly dumb.

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What is the total number of rabbits in the neighborhood in year 2
lawyer [7]

Answer:

6

Step-by-step explanation:

5 0
3 years ago
PLEASE HELP ME PLEASE PLEASE
mezya [45]
1)

Break up the irregular shape into two rectangles

12 * 4.5 = 54
2 * 5 = 10
54 + 10 = 64 cm^2

2)

Break up the irregular shape into a triangle and rectangle

24 * 8 = 192

To get the base of the triangle:
24 - 6 - 6 = 12
To get the height of the triangle:
16 - 8 = 8

1/2(12 * 8) = 48

192 + 48 = 240 yd^2

3)

Separate into triangle and semi circle

To get the base: 8 * 2 = 16

1/2(15 * 16) = 120

(pi (8)^2)/2 = 100.5

120 + 100.5 = 220.5 cm^2

4)

Separate half circle from rectangle

(pi (7.5)^2)/2 = 88.4

7 * 15 = 105

88.4 + 105 = 193.4 m^2

5)

Separate triangle from trapezoid

2.8 * 7 = 19.6

(7+9/2)(3.6) = 28.8

19.6 + 28.8 = 48.4 ft^2

6)

Separate semi circle from trapezoid

(pi(3)^2)/2 = 6.3

(6+10/2)(8) = 64

6.3 + 64 = 70.3 yd^2

8 0
3 years ago
BRAINLIEST!!! Can someone tell me how to graph inequalities?
3241004551 [841]

Answer:

whichever way the opening of the sign points go the opposite. if it is less than or equal to, closed circle

Step-by-step explanation:

>

the line would point this way -->

sorry if this doesnt help

8 0
3 years ago
Read 2 more answers
Factorize 2a^2+7a-15​
loris [4]

\huge\bf  \pink {\underline{Solution :-}}

2 {a}^{2}  + 7a - 15

= 2 {a}^{2}  + 10a - 3a - 15

= 2a(a + 5) - 3(a + 5)

= (a + 5)(2a - 3)

\sf \red{Hence, Answer \:  is  \: (a + 5)(2a - 3).}

\\

\bf \purple{ \underline{ Important  \: Formulas  \: for  \: Factorization :-}}

• \:  {a}^{2}  + 2ab + {b}^{2} =  {(a + b)}^{2}

• \: (a + b)(a - b) =  {a}^{2}  -  {b}^{2}

• \:  {a}^{2} - 2 ab  +  {b}^{2}  =  {(a - b)}^{2}

• \:  {a}^{3}  + 3 {a}^{2} b + 3a {b}^{2}  +  {b}^{3} =  {(a + b)}^{3}

• \:  {a}^{3}   -  3 {a}^{2} b + 3a {b}^{2}   -  {b}^{3} =  {(a  - b)}^{3}

•  \:  {(a + b)}^{2}  +  {(a - b)}^{2}  = 2( {a}^{2}  +  {b}^{2} )

• \: {(a + b)}^{2}   -   {(a - b)}^{2}  = 4ab

• \: (a + b)( {a}^{2}   -ab   +  {b}^{2}  ) =  {a}^{3}  +  {b}^{3}

• \: (a  -  b)( {a}^{2}    + ab   +  {b}^{2}  ) =  {a}^{3}   -  {b}^{3}

• \:   {( \frac{a + b}{2} )}^{2}  - ( {\frac{a - b}{2} } )^{2}  = ab

5 0
3 years ago
Read 2 more answers
Please help thank you very much
-BARSIC- [3]
Hello!

The answer is 34°

Hope this helps!
7 0
3 years ago
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