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2 years ago

6

Is the value 5 a solution to the inequality r + 4 < 7 ?

2 answers:

docker41 [41]2 years ago

8 0

Answer:

No, i don't think so

Step-by-step explanation:

saveliy_v [14]2 years ago

7 0

Answer:

no

Step-by-step explanation:

5+4=9 which is greater than 7

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The formula to determine the period of one swing of a simple pendulum is

Sonbull [250]

Answer:

byfyfutxfjjtudhxfuxhfxfjcgjv

Step-by-step explanation:

I don't no

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3 years ago

From 9pm to 6am the tempeture dropped 1.6 degrees Fahrenheit per hour what was the total change in temperature in degrees Fahren

aalyn [17]

1.6 (degrees) x 9 (hours) = 14.4 degrees

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2 years ago

How to find imaginary zeros anf real zeros of F(x)=-4x^5-8x^3+12x

Fofino [41]

Answer:

$x=\{0, -1, 1, -i\sqrt{3}, i\sqrt{3}\}$

Step-by-step explanation:

We are given the function:

$f(x)=-4x^5-8x^3+12x$

And we want to finds its zeros.

Therefore:

$0=-4x^5-8x^3+12x$

Firstly, we can divide everything by -4:

$0=x^5+2x^3-3x$

Factor out an x:

$0=x(x^4+2x^2-3)$

This is in quadratic form. For simplicity, we can let:

$u=x^2$

Then by substitution:

$0=x(u^2+2u-3)$

Factor:

$0=x(u+3)(u-1)$

Substitute back:

$0=x(x^2+3)(x^2-1)$

By the Zero Product Property:

$x=0\text{ and } x^2+3=0\text{ and } x^2-1=0$

Solving for each case:

$x=0\text{ and } x=\pm\sqrt{-3}\text{ and } x=\pm\sqrt{1}$

Therefore, our real and complex zeros are:

$x=\{0, -1, 1, -i\sqrt{3}, i\sqrt{3}\}$

4 0

2 years ago

Three times a number, x, increased by four is equal to five times the number, x. Which equation can be used to solve for x?

Dimas [21]

3x+4=5x
4=5x-3x
4=2x
X=2

4 0

3 years ago

Read 2 more answers

4 (9x+6) = 36x - 7 what does x =

koban [17]

Since 24= - 7 is false , there is No solution

8 0

3 years ago