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schepotkina [342]
3 years ago
6

What is the mean, median, and mode of 6,2,3,4,4,2,8,5,2​

Mathematics
1 answer:
bearhunter [10]3 years ago
5 0

Answer:

Mode=2

Median=4

Step-by-step explanation:

Mode you add all the numbers and divide by the actual number of the numbers given.

Median you cancel the numbers from first to last until you reach the one in the middle that's going to be the median.

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hope i was able to help and i wasn’t to late.
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1st option

Step-by-step explanation:

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7 0
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Yanka [14]

Step-by-step explanation:

c(n) =  \frac{4}{9} ( - 3)^{n - 1}   \\   \\  \therefore \: c(3) =  \frac{4}{9} ( - 3)^{3- 1}   \\   \\  \therefore \: c(3) =  \frac{4}{9} ( - 3)^{2}   \\   \\  \therefore \: c(3) =  \frac{4}{9}  \times 9   \\   \\   \huge{ \purple{ \boxed{\therefore \: c(3) = 4}}}

8 0
4 years ago
The time it takes to travel a fixed distance varies inversely with the speed traveled. It takes
uysha [10]

first off, let's notice that Purple's time is in minutes, whilst the rate is in miles per hour, the units of both must correspond, so, we can either change the time from minutes to hours or the rate from hours to minutes, hmmm let's change the time to hours.

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\qquad \qquad \textit{inverse proportional variation} \\\\ \textit{\underline{y} varies inversely with \underline{x}} ~\hspace{6em} \stackrel{\textit{constant of variation}}{y=\cfrac{\stackrel{\downarrow }{k}}{x}~\hfill } \\\\ \textit{\underline{x} varies inversely with }\underline{z^5} ~\hspace{5.5em} \stackrel{\textit{constant of variation}}{x=\cfrac{\stackrel{\downarrow }{k}}{z^5}~\hfill } \\\\[-0.35em] ~\dotfill

\stackrel{\begin{array}{llll} \textit{\tiny "t"ime varies}\\ \textit{\tiny inversely with "s"peed} \end{array}}{t = \cfrac{k}{s}}\qquad \textit{we know that} \begin{cases} t=\stackrel{minutes}{40}\to \stackrel{hrs}{\frac{2}{3}}\\ s=\stackrel{m/h}{9} \end{cases} \implies \cfrac{2}{3}~~ = ~~\cfrac{k}{9} \\\\\\ 18=3k\implies \cfrac{18}{3}=k\implies 6=k~\hfill \boxed{t=\cfrac{6}{s}} \\\\\\ \textit{when s = }\stackrel{m/h}{12}\textit{ what is "t"?}\qquad t=\cfrac{6}{12}\implies t=\cfrac{1}{2}

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2 years ago
What is the solution to the inequality below (NO WRONG ANSWER PLEASE
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A is the answer

I used an app
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