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3 years ago

Given F(x) = 3x 2 - 4, find F(-√3). a)-13 b)5 c)23

Mathematics

2 answers:

svet-max [94.6K]3 years ago

8 0

I want to say 5 but I'm not sure

djyliett [7]3 years ago

7 0

Answer

Step-by-step explanation:

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How to answer this problem solving question: Anita and Terry ride the subway on sundays to visit their grandparents. There are 2

Dovator [93]

We know that they have:
2 entrences
3 ways to chose (escalator,elevator and stairs)
8 gates
and again 3 ways to chose (escalator, elevator and stairway)

now you have to multiply it:
$2*3*8*3=6*8*3=48*3=144$

There are 144 different ways that Anita and Terry can go from street level to the trains:)

4 0

3 years ago

What is the greatest common factor and least common multiple of 4 and 10?

rusak2 [61]

Answer:

The greatest common factor of 4 and 10 is 2, and the Least common multiple of 4 and 10 is 20

Step-by-step explanation:

3 0

3 years ago

What is the value of x in the eqation 5[x-6] = 2 [x+3]

topjm [15]

Answer:

x = 12

Step-by-step explanation:

5x - 30 = 2x + 6

3x = 36

x = 12

8 0

3 years ago

Read 2 more answers

What is the image of point (-6,1) after the reflection over the line y=2

Lynna [10]

The image is (-6, 3)

Hope it helps!

5 0

3 years ago

A laboratory scale is known to have a standard deviation (sigma) or 0.001 g in repeated weighings. Scale readings in repeated we

weqwewe [10]

Answer:

99% confidence interval for the given specimen is [3.4125 , 3.4155].

Step-by-step explanation:

We are given that a laboratory scale is known to have a standard deviation (sigma) or 0.001 g in repeated weighing. Scale readings in repeated weighing are Normally distributed with mean equal to the true weight of the specimen.

Three weighing of a specimen on this scale give 3.412, 3.416, and 3.414 g.

Firstly, the pivotal quantity for 99% confidence interval for the true mean specimen is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean weighing of specimen = $\frac{3.412+3.416+3.414}{3}$ = 3.414 g

$\sigma$ = population standard deviation = 0.001 g

n = sample of specimen = 3

$\mu$ = population mean

<em>Here for constructing 99% confidence interval we have used z statistics because we know about population standard deviation (sigma).</em>

So, 99% confidence interval for the population mean, $\mu$ is ;

P(-2.5758 < N(0,1) < 2.5758) = 0.99 {As the critical value of z at 0.5% level

of significance are -2.5758 & 2.5758}

P(-2.5758 < $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ < 2.5758) = 0.99

P( $-2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ < ${\bar X - \mu}$ < $2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.99

P( $\bar X-2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.99

<u>99% confidence interval for</u> $\mu$ = [ $\bar X-2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ , $\bar X+2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ ]

= [ $3.414-2.5758 \times {\frac{0.001}{\sqrt{3} } }$ , $3.414+2.5758 \times {\frac{0.001}{\sqrt{3} } }$ ]

= [3.4125 , 3.4155]

Therefore, 99% confidence interval for this specimen is [3.4125 , 3.4155].

6 0

3 years ago