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zloy xaker [14]
3 years ago
5

How can photography allow us to view the world around us in different ways?

Computers and Technology
2 answers:
QveST [7]3 years ago
8 0

Photography is an art that allows us to see the world with more detail and capture beauty around us up close or from a distance. Most photographers see the world differently from the rest of us. Photography gives us the sense and feel of what others feel. It defines actions. For example, on road trips, photographers experience very many ‘stop the car now’ moments. We also have moments at airports, nature walks and millions of situations. We see abstractly and literally. Photography helps us define the world and makes us think about how we change the world around us

Ymorist [56]3 years ago
6 0
It captures a single moment that one might not see with a naked eye. It shows the beauty and the essence of simple things in one exact moment. And it allows the viewer to take more time to reflect on what is captured and really find meaning within it.
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How can a search be narrowed to only search a particular website????
vesna_86 [32]

Answer:

There are a variety of ways to narrow down your search results in a library database. The two most direct ways are to focus your search with more specific keywords and/or to limit by various criteria before or after searching. The more specific you are with your search terms, the more relevant your results will be

Hope it helped!!!

4 0
3 years ago
What is the output of the second println statement in the main method, public class foo { int i ; static int s ; public sttic vo
Sedaia [141]

Answer:

b) f2.i is 1 f2.s is 2

Explanation:

i is an instance variable and s is static, shared by all objects of the Foo class.

6 0
3 years ago
write the algorithm, flowchart and BASIC program to calculate the area of the rectangle length 50m and width 30m.​
GalinKa [24]

Answer:

The Basic Program is as follows:

10 LENGTH = 50

15 WIDTH = 30

20 AREA = WIDTH * LENGTH

25 PRINT AREA

30 END

The Algorithm is as follows:

1. Start

2. Let Length = 50

3. Let Width = 30

4. Compute Area = Length * Width

5. Display Area

6. Stop

See Attachment for flowchart (flowchart is designed using draw io tools)

Explanation:

The flowchart, algorithm and basic program all follow the same sequence and explanation

Using the basic program as a case study;

Line number 10: The program starts by initializing LENGTH to 50

Line number 15: It then initializes WIDTH to 30

Line number 20: The AREA is calculated by LENGTH * WIDTH

Line number 25: The value of AREA is printed afterwards

Line number 30: Lastly, the program stops execution

8 0
3 years ago
Help with some questions. Thank you!
Oksana_A [137]

Answer:

1. E: II and III only

2. A: (int)(Math.random() * (upper − lower) ) + lower

3. A: The value of answer is N

4. E: while( !(userGuess == secretNumber) && numGuesses <= 15 )

5. C: 21

Explanation:

1. Which of the following is equivalent to while(userGuess != secretNumber)?

I. while( userGuess < secretNumber && userGuess > secretNumber)  

NO - This will test until the userGuess is smaller AND greater than the secretNumber, at the same time... so that condition will never be true.

II. while( userGuess < secretNumber || userGuess > secretNumber)

YES - This will test the value of userGuess and see if it's smaller OR greater than secetNumber.  So, it will loop until the user guesses right.

III. while( !(userGuess == secretNumber) )

YES, this will negate the match with the secretNumber.  In order words, if it's not a match, it will return true... so the loop will run until it finds a false condition (a match).

As you can see, only II and III are valid.

2.  If the lower limit were inclusive and the upper limit exclusive, which expression would properly generate values for the secret number?

A: (int)(Math.random() * (upper − lower) ) + lower

Since the lower limit is INCLUSIVE, we mustn't add one to the lower limit.  Also, the Math.random() function returns a value that matches our needs; it returns a value between [0,1[ (meaning the 0 is included, but not the 1).

Assuming the (int) caster does return only the integer portion doing a round down of the result, we'll be perfect.

3. What conclusion can be made about the state of the program when the while loop terminates?

while(!answer.equals( "N"))

{.....

A: The value of answer is N

The condition in the loops reads as "While the negation of the answer being 'N', loop".  If the answer equals 'N' then the method should return true... which will be negated by the '!' operator, causing the condition to be false. Thus we know that if the loop ends, the value of answer contains 'N', any other value will keep the loop going.

4. Assuming numGuesses is initialized to 1, how would the while statement be modified to include an extra criterion limiting the number of guesses to 15?

E: while( !(userGuess == secretNumber) && numGuesses <= 15 )

This modified condition will first test to see if the user has guessed the secretNumber (if he has, the first sub-parenthesis will be true... so the left side of the && operator will be false due to the negation operator.  The right side of the && operator will check to see how many tries have been attempted. Since the counter starts at 1, it needs to go up to 15 inclusively... so the <= is the right comparison operator.

5. After execution of the following code segment, what will be displayed?

int x = 1;

while(x < 18)

{

x += 5;

}

System.out.println(x);

C: 21

The x variable is initialized with 1... then enters the loop, in which it is incremented by 5 at each passage.

So after first passage, x = 6

After second passage, x = 11

After third passage, x = 16

After fourth passage, x = 21

Cannot enter the loop again because 21 > 18.

So, it will print out the value of 21.

3 0
3 years ago
Jayden wants to take a current theme but just change a little bit of it. Complete the steps to help Jayden.
Sindrei [870]

Answer:The theme can be automatically changed via the default settings

Explanation:

4 0
2 years ago
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