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Wewaii [24]
3 years ago
8

What is the answer to (8+5) to the 2nd power +(15 Divided by 5) =

Mathematics
2 answers:
Alenkinab [10]3 years ago
7 0
The answer is to this is 172
gavmur [86]3 years ago
4 0

(8+5)^2 + (15/5)

8 + 5 = 13

13 * 13 = 169

169 + (15/5)

15/5 = 3

169 + 3

172

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Answer: im not sure

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Simplify 5 - 2 · 3 + 4. 13 -5 3 21
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What is the slope of the line?​
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➷ Slope = rise/ run

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7 0
3 years ago
I don’t understand how to find the dimension,<br> Need help :c
slava [35]

Width = W

Length = 2 times the width plus 3 feet = 2W + 3

Area of triangle A = L * W

A = W (2W + 3)

20 = 2W^2 + 3W

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W + 4 = 0; W = - 4 (width cannot be negative, excluded)

2W - 5 = 0

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Width = 2.5 feet and Length = 8 feet

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8 0
2 years ago
ISTEP IS COMING UP AND IM NOT READY!!!
AlekseyPX

> and < with the lines under it mean that they can also be equal to the constant on the other side (greater/less than or equal to)

So x <= 3 can be anything less than 3 and 3.

*the = in this inequality is the equivalent of a line

Now vice versa.

x => 3 can be anything greater than 3 and 3.

Now for the dots.

The open dots in signs are (< and >).

Basically they start at that point they are on but don't include it.

So an open dot at 3 pointing to the left means that the value is greater than 3 but does not include 3.

The closed dots in signs are (<= and =>).

They start at the point and include it.

So a closed dot a 3 pointing to the left means that the value is greater than 3 and includes 3.

Arrows.

Arrows pointing to the left mean that the values are getting bigger.

Arrows pointing to the right mean that the values are getting smaller.

ie : An arrow pointing to the left with a starting point at 3 = 3 and anything bigger, such as 4.

ie : An arrow pointing to the right with a starting point at 3 = 3 and anything smaller, such as 2.

Solve for problems.

The main concept is isolate the variable.

This basically means make the variable be lonely ^^

Use +, -, *, and /

Ex : 6x + 2 > 3

First, we would subtract 2 from both sides.

6x > 1

Then, we would divide each side by 6, leaving the x alone.

x > 1/6

And voila! x is anything greater than 1/6 but it does not include 1/6.

Hope this helps! ^^

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