Given :
A circle is inscribed in a square with a side length of 144.
So, radius of circle, r = 144/2 = 72 units.
To Find :
The probability that the point is inside the circle.
Solution :
Area of circle,

Area of square,

Now, probability is given by :

Therefore, the probability that the point is inside the circle is 0.785 .
It is B 4.4
Because of 2.2 is the first one and the second one should be 4.4 so it B. 4.4
Answer:
Step-by-step explanation:
b/c the function goes thur the point (1,4) we know it's 4 times more than f(x) so g(x) = 4
We need to account for both x values on either side of the length, and width.
Thus, the length becomes 10 + x + x = 10 + 2x
and the width becomes 5 + x + x = 5 + 2x
For the second question, I'm assuming we don't account for the area that is covered by the garden.
Then we can say that the path is measured by: (5 + 2x)(10 + 2x) - 50, which is the area of the garden itself.
(5 + 2x)(10 + 2x) - 50 = 54
Expanding the brackets:






x = -9, or x = 3/2
Since x > 0, then x ≠ -9
Thus, the only x-value we can take is x = 3/2
(20+2.5)x = cost
when x equals number of tickets
(20+2.5)24 = 540