The equation of a line that goes through the point (x1,y1) and has a slope of m is
y-y1=m(x-x1)
so, given the point (-2,8)
x1=-2
y1=8
y-8=m(x-(-2))
y-8=m(x+2)
the equation is y-8=m(x+2) where m is the slope
or you could rewrite it to get y=mx+2m+8
Step-by-step explanation:
Substitute r = 3 and h = 5 into the formula. Volume V=13⋅π⋅9⋅5=15πcm3=47.1cm3.
C) it is a closed figure made up of straight lines.
Answer:
p = 5,624
Step-by-step explanation:
(32,476 + p) / 381 = 100
multiply both sides by 381
32,476 + p = 38,100
Subtract 32476 from both sides
p = 5,624
Answer:
x+3y-6=0
Step-by-step explanation:
given eqn is y=3x-2 which is 3x-y-2=0
the eqn of line perpendicular to given eqn is -x+3y+k=0
it passes through (6,4)
-6+3*4+k=0
or,. -6+12+k=0
or, k= -6
therefore, the eqn of line perpendicular to given eqn is x+3y-6=0
