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Zarrin [17]
3 years ago
5

Please help me with this

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
3 0

Answer:

13.7 cm²

Step-by-step explanation:

area of yellow region = area of square - area of 4 quarter circles

area of square = 8² = 64

area of 4 congruent quarter circles = area of circle

area of circle with radius = 4

A = π × 4² = 16π

yellow region = 64 - 16π ≈ 13.7 cm²

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Jim is hiking 4 1/2 mile trail.He has already hiked 2 5/8 miles.How much further does he have to hike?
musickatia [10]

Answer:

1 7/8

Step-by-step explanation:

2 5/8

+1 7/8= 4 1/2

  1. 7=3+4
  2. 5+3=8
  3. 2 5/8 + 3/8= 3
  4. 3 + 1= 4
  5. 4 + 4/8= 4 4/8
  6. 4 4/8 = 4 1/2

3 0
3 years ago
-5t = -45 please help
gladu [14]

Answer:

t = 9

Step-by-step explanation:

8 0
3 years ago
If Carl, Steve and John have 40 sweets to share and John gets the most out of all three. What’s the smallest amount he can get?
Basile [38]

Answer:

13 +13 +14 ensures he is getting the smallest amount so its 14

Step-by-step explanation:

6 0
3 years ago
A bag has 30 towels numbered 1 to 30. What's the ratio for odds to evens?
8090 [49]
15:15

Which is simplified to
1:1

Hope this helps!
8 0
3 years ago
If the right side of the equation dy dx = f(x, y) can be expressed as a function of the ratio y/x only, then the equation is sai
melomori [17]

Answer:

 y = x*sqrt(Cx - 1)

Step-by-step explanation:

Given:

                                  dy / dx = (x^2 + 5y^2) / 2xy

Find:

Solve the given ODE by using appropriate substitution.

Solution:

- Rewrite the given ODE:

                               dy/dx = 0.5(x/y) + 2.5(y/x)

- use substitution y = x*v(x)

                               dy/dx = v + x*dv/dx

- Combine the two equations:

                                v + x*dv/dx = 0.5*(1/v) + 2.5*v

                                x*dv/dx = 0.5*(1/v) + 1.5*v

                                x*dv/dx = (v^2 + 1) / 2v

-Separate variables:

                                 (2v.dv / (v^2 + 1) = dx / x  

- Integrate both sides:

                                 Ln (v^2 + 1) = Ln(x) + C

                                 v^2 + 1 = Cx

                                 v = sqrt(Cx - 1)

- Back substitution:

                                (y/x) = sqrt(Cx - 1)

                               y = x*sqrt(Cx - 1)

                         

3 0
3 years ago
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