What is the vertex of the absolute value function defined by f(x) = (x + 2) + 4?

URGENT!!!

Makovka662 [10]

Answer:

Train A - 50 miles per hour

train B - 30 miles per hour

Step-by-step explanation:

Let x mph be the speed of the train B, then the speed of the train A is (x+20) mph.

In 3 hours,

train A travels 3(x+20) miles
train B travels 3x miles

In total, they covered the distance of 240 miles, so

$3(x+20)+3x=240\ \ \ \text{[Divide by 3]}\\ \\x+20+x=80\\ \\2x=80-20\\ \\2x=60\\ \\x=30\ mph\\ \\x+20=30+20=50\ mph$

8 0

2 years ago

What fraction is bigger 5/8 or 7/15

Zolol [24]

5/8=.625 and 7/15=.466 repeating so 5/8 is a bigger fraction

6 0

2 years ago

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An article contained the following observations on degree of polymerization for paper specimens for which viscosity times concen

devlian [24]

Answer:

(a) A 95% confidence interval for the population mean is [433.36 , 448.64].

(b) A 95% upper confidence bound for the population mean is 448.64.

Step-by-step explanation:

We are given that article contained the following observations on degrees of polymerization for paper specimens for which viscosity times concentration fell in a certain middle range:

420, 425, 427, 427, 432, 433, 434, 437, 439, 446, 447, 448, 453, 454, 465, 469.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean = $\frac{\sum X}{n}$ = 441

s = sample standard deviation = $\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }$ = 14.34

n = sample size = 16

$\mu$ = population mean

Here for constructing a 95% confidence interval we have used One-sample t-test statistics as we don't know about population standard deviation.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-2.131 < $t_1_5$ < 2.131) = 0.95 {As the critical value of t at 15 degrees of

freedom are -2.131 & 2.131 with P = 2.5%}

P(-2.131 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.131) = 0.95

P( $-2.131 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.131 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-2.131 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.131 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X -2.131 \times {\frac{s}{\sqrt{n} } }$ , $\bar X +2.131 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $441-2.131 \times {\frac{14.34}{\sqrt{16} } }$ , $441+2.131 \times {\frac{14.34}{\sqrt{16} } }$ ]

= [433.36 , 448.64]

(a) Therefore, a 95% confidence interval for the population mean is [433.36 , 448.64].

The interpretation of the above interval is that we are 95% confident that the population mean will lie between 433.36 and 448.64.

(b) A 95% upper confidence bound for the population mean is 448.64 which means that we are 95% confident that the population mean will not be more than 448.64.

6 0

3 years ago

I need to find the product of f and g. what is the domain and range of the product

velikii [3]

Step-by-step explanation:

Putting both functions into a graphing calculator, we can easily find the domain and range. (attatched)

By looking at the graph, we can tell that f(x) is a quadratic function because of the symmetry. We can also tell that it never goes below 4. Knowing this, we can determine the domain and range.

Domain: {x | all real numbers}

Range: {y | y > 4}

By looking at the graph, we can tell that g(x) is an exponential function because it has a curve, and never goes below the x. Knowing this, we can determine the domain and range.

Domain: {x | all real numbers}

Range: {y | y > 0}

7 0

2 years ago

Please help me with these 2 questions!!

IceJOKER [234]

Answer: 53. B similar

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers