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motikmotik
3 years ago
15

What is the first step in constructing an inscribed circle inside of triangle XYZ?

Mathematics
1 answer:
Rina8888 [55]3 years ago
6 0

Answer:

A

Step-by-step explanation:

construct the perpendicular bisector of segment xy

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The slope formula can be used to prove that a triangle has
OverLord2011 [107]

Answer:

The slope formula can be used to prove that a triangle has

A. Congruent Sides

<u>B. A right angle </u>

C. Parallel sides

D.Congruent angles

Step-by-step explanation:

The formula for finding the slope of a line on a coordinate plane is (y2 - y1) / (x2 - x1), where (x2, y2) and (x1, y1) represent two distinct points on the line. This is also known as "change in y over change in x" or "rise over run."

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3 years ago
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Please help me! I don’t understand
Sedaia [141]

Answer:

Step-by-step explanation: Ok so it is backwerd to pas would be nagitv

3 0
2 years ago
Need help for question 8 and 9. I need the equation that’s passes through the points!
dsp73

Answer:

Step-by-step explanation:

Question 8

Let the equation of a line passing through two points (x_1,y_1) and (x_2,y_2) is given by,

y = mx + b

Here, m = slope and y-intercept = b

Since, m = \frac{y_2-y_1}{x_2-x_1}

For two points (1, 4) and (5, 8),

m = \frac{8-4}{5-1}

m = 1

Equation will be,

y = (1)x + b

y = x + b

Since, this line passes through (1, 4),

4 = 1 + b

b = 3

Therefore, equation of the line will be,

y = x + 3

Question 9

Let the equation is y = mx + b

m = \frac{y_2-y_1}{x_2-x_1}

For two points (2, 10) and (6, 4)

m = \frac{10-4}{2-6}

m = -\frac{3}{2}

By substituting the value of 'm' in the equation,

y = -\frac{3}{2}x+b

Since, this line passes through (2, 10)

10 = -\frac{3}{2}(2)+b

b = 10 + 2

b = 12

Therefore, equation of the line will be,

y=-\frac{3}{2}x+12

4 0
3 years ago
In ΔEFG, the measure of ∠G=90°, GF = 48, EG = 55, and FE = 73. What ratio represents the cosecant of ∠F?
Mrac [35]

Answer:

Cosec <F = 73/55

Step-by-step explanation:

In ΔEFG, the measure of ∠G=90°, GF = 48, EG = 55, and FE = 73. What ratio represents the cosecant of ∠F?

First you must know that;

Cosecant <F = 1/sin<F

Given

∠G=90°, GF = 48, EG = 55, and FE = 73.

ED ,= hyp = 73

EG = opp = 55*side facing <F

Using DOH CAH TOA

Sin theta = opp/hyp

Sin <F= 55/73

Reciprocate both sides

1/sinF = 73/55

Cosec <F = 73/55

3 0
3 years ago
Which of the following is the area of the special trapezoid if AB = 10, CD = 10, and the height is 8.
Lelu [443]
Area of a trapezoid is A=height over 2 B1 +B2, so 10+10=20, then 20(8)=160, 160/2=80. Answer is b.
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