Answer:
With what?
Step-by-step explanation:
If I'm correct the answer would be C.) hope this help
Answer:
1. b ∈ B 2. ∀ a ∈ N; 2a ∈ Z 3. N ⊂ Z ⊂ Q ⊂ R 4. J ≤ J⁻¹ : J ∈ Z⁻
Step-by-step explanation:
1. Let b be the number and B be the set, so mathematically, it is written as
b ∈ B.
2. Let a be an element of natural number N and 2a be an even number. Since 2a is in the set of integers Z, we write
∀ a ∈ N; 2a ∈ Z
3. Let N represent the set of natural numbers, Z represent the set of integers, Q represent the set of rational numbers, and R represent the set of rational numbers.
Since each set is a subset of the latter set, we write
N ⊂ Z ⊂ Q ⊂ R .
4. Let J be the negative integer which is an element if negative integers. Let the set of negative integers be represented by Z⁻. Since J is less than or equal to its inverse, we write
J ≤ J⁻¹ : J ∈ Z⁻
Answer: X = -12
Step-by-step explanation: 1) 12 + x/4 = 9
2) 12 + x/ 2^2 = 9
3) x/ 2^2 + 12 = 9
Answer:
There are 38 premium tickets and 82 regular tickets in a pile.
Step-by-step explanation:
Given,
Total number of tickets = 120
Total amount = $5812
Solution,
Let the number of premium tickets be x.
And the number of regular tickets be y.
Total number of tickets is the sum of total number of premium tickets and total number of regular tickets.
So the equation can be written as;

Again,total amount is the sum of total number of premium tickets multiplied by cost of each premium ticket and total number of regular tickets multiplied by cost of each regular ticket.
So the equation can be written as;

Now We will multiply equation 1 by 25 we get;

Now Subtracting equation 3 from equation 2 we get;

We will now substitute the value of x in equation 1 we get;

Hence There are 38 premium tickets and 82 regular tickets in a pile.