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4 years ago

The graph shows the relationship between the distance a truck can travel and the amount of gasoline used.

Mathematics

2 answers:

antoniya [11.8K]4 years ago

5 0

<span>The graph shows the relationship between the distance a truck can travel and the amount of gasoline used.

Unit rate is define as the rise over the run or distance covered per unit time.
In this case :
Rate = 28 / 4 = 7 mpg

</span>

RUDIKE [14]4 years ago

3 0

Slope - Intercept form formula: y = mx + b
'm' represents the slope (unit rate)
'b' represents the y - intercept

Equation: y = 7x
Slope (unit rate): 7
Y-Intercept: 0

If you used 5 gallons of gasoline, you go 5 times the number of miles, which is 7, to get a total amount of 35 miles.
Unit rate = 7
The answer is B.

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4 years ago

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3 years ago

What happens to the sign or signs of the coordinates when you reflect a point?

elena55 [62]

Part a: Reflecting a point across the x-axis, changes the sign of the y-coordinate.

Part b: Reflecting a point across the y-axis, changes the sign of the x-coordinate.

Part c: Reflecting a point across both the axes, changes the signs of both the coordinates.

Explanation:

Part a: Reflecting a point across the x-axis

The reflection is a transformation of a figure which represents a flip.

The rule for a reflection over the x -axis is given by

$(x, y) \rightarrow(x,-y)$

Hence, this represents the change of sign of the y-coordinate.

Thus, Reflecting a point across the x-axis, changes the sign of the y-coordinate.

Part b: Reflecting a point across the y-axis

The rule for a reflection over the y -axis is given by

$(x, y) \rightarrow(-x, y)$

Hence, this represents the change of sign of the x-coordinate.

Thus, Reflecting a point across the y-axis, changes the sign of the x-coordinate.

Part c: Reflecting a point across both the axes

The rule for a reflection across both the axes is given by

$(x, y) \rightarrow(-x, -y)$

Hence, this represents the changes the signs of both the coordinates.

Thus, Reflecting a point across both the axes, changes the signs of both the coordinates.

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3 years ago

Find the perimeter of quadrilateral PQRS with the vertices P(2,4), Q(2,3), R(-2,-2), and S(-2,3).

storchak [24]

Answer:

$P=16.53\ units$

Step-by-step explanation:

we know that

The perimeter of quadrilateral PQRS is equal to the sum of its four length sides

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

the vertices P(2,4), Q(2,3), R(-2,-2), and S(-2,3)

step 1

Find the distance PQ

P(2,4), Q(2,3)

substitute in the formula

$d=\sqrt{(3-4)^{2}+(2-2)^{2}}$

$d=\sqrt{(-1)^{2}+(0)^{2}}$

$d=\sqrt{1}$

$dPQ=1\ unit$

step 2

Find the distance QR

Q(2,3), R(-2,-2)

substitute in the formula

$d=\sqrt{(-2-3)^{2}+(-2-2)^{2}}$

$d=\sqrt{(-5)^{2}+(-4)^{2}}$

$dQR=\sqrt{41}\ units$

step 3

Find the distance RS

R(-2,-2), and S(-2,3)

substitute in the formula

$d=\sqrt{(3+2)^{2}+(-2+2)^{2}}$

$d=\sqrt{(5)^{2}+(0)^{2}}$

$dRS=5\ units$

step 4

Find the distance PS

P(2,4), S(-2,3)

substitute in the formula

$d=\sqrt{(3-4)^{2}+(-2-2)^{2}}$

$d=\sqrt{(-1)^{2}+(-4)^{2}}$

$dPS=\sqrt{17}\ units$

step 5

Find the perimeter

$P=PQ+QR+RS+PS$

substitute the values

$P=1+\sqrt{41}+5+\sqrt{17}$

$P=6+\sqrt{41}+\sqrt{17}$

$P=16.53\ units$

5 0

3 years ago

WHAT IS THE RIGHT ANSWER? HELP PLS!

Art [367]

<h3>Answer: Choice B</h3>

=============================================

Explanation:

If you graphed the equation 2x-5y = 14, you'll find it has a positive slope. It turns out the slope in this equation is 2/5, which is positive. A positive slope means the line goes uphill as you move from left to right. This means we can rule out choice because of this (since we want the line to slope downward).

Now let's turn to choice D. If we multiply both sides of the first inequality by -1, then we go from $-2x-5y \le 14$ to $2x+5y \ge -14$ . Note the inequality sign flips. This always happens when we multiply both sides by any negative number. The inequality $2x+5y \ge -14$ implies that the shaded region will be above the boundary line, but this contradicts the drawing which shows the shaded region is below the diagonal boundary line. We can rule out choice D because of this. Choice A can be ruled out for similar reasoning.

You should find that only choice B is left. The diagonal line is 2x+5y = 14, and we shade below this boundary line, as well as shading to the right of the y axis (to indicate all values have positive x coordinates). Values on the boundary count as solution points as well.

3 0

3 years ago