All categories

3 years ago

The graph shows the relationship between the distance a truck can travel and the amount of gasoline used.

Mathematics

2 answers:

antoniya [11.8K]3 years ago

5 0

<span>The graph shows the relationship between the distance a truck can travel and the amount of gasoline used.

Unit rate is define as the rise over the run or distance covered per unit time.
In this case :
Rate = 28 / 4 = 7 mpg

</span>

RUDIKE [14]3 years ago

3 0

Slope - Intercept form formula: y = mx + b
'm' represents the slope (unit rate)
'b' represents the y - intercept

Equation: y = 7x
Slope (unit rate): 7
Y-Intercept: 0

If you used 5 gallons of gasoline, you go 5 times the number of miles, which is 7, to get a total amount of 35 miles.
Unit rate = 7
The answer is B.

You might be interested in

Solve: 14 = k(0.4) k = _____

KatRina [158]

Let's solve your equation step-by-step.

14=k(0.4)

Step 1: Simplify both sides of the equation.

14=0.4k

Step 2: Flip the equation.

0.4k=14

Step 3: Divide both sides by 0.4.

$\frac{0.4k}{0.4}$ = $\frac{14}{0.4}$

4 0

3 years ago

Read 2 more answers

Can someone please help me... I am totally confusedd!!!

Bas_tet [7]

The length would be 6

3 0

3 years ago

Consider the following frequency distribution:

daser333 [38]

Answer:

Relative frequency

0.214

0.268

0.446

0.071

Total 1

Step-by-step explanation:

The relative frequency is computed by dividing the individual frequencies to the sum of frequencies.

sum of frequencies=12+15+25+4=56

Class Relative Frequency

10-20 12/56=0.214

20-30 15/56=0.268

30-40 25/56=0.446

40-50 4/56=0.071

Total 12/56+15/56+25/56+4/56=56/56=1

8 0

3 years ago

Simplify and Evaluate

zalisa [80]

$\dfrac{2^{-1} + 5^{-1}}{10^{-1} - 5^{-2}} =$

$= \dfrac{\frac{1}{2} + \frac{1}{5}}{\frac{1}{10} - \frac{1}{5^2}}$

$=\dfrac{\frac{1}{2} + \frac{1}{5}}{\frac{1}{10} - \frac{1}{25}}$

$=\dfrac{\frac{5}{10} + \frac{2}{10}}{\frac{5}{50} - \frac{2}{50}}$

$=\dfrac{\frac{7}{10}}{\frac{3}{50}}$

$= \frac{7}{10} \times \frac{50}{3}$

$= \frac{7}{1} \times \frac{5}{3}$

$= \frac{35}{3}$

4 0

3 years ago

Factor the expression.

tiny-mole [99]

B. (k+10f)(k-5f) you can tell in 2 ways. 1. if the second sign is neg then the signs in the factors are going to be one neg and one positive so that knocks out C and D. Then you look at the second term and since the 5 is positive then the 10 has to be positive so you end up with a positive 5kf.

The second way is to FOIL them out. When you check B you get $k^{2} -5kf+10kf- 50f^{2}$ combine your like terms and you have your original expression of $k^{2} +5kf-50 f^{2}$

Hope that helps

3 0

3 years ago