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Blababa [14]
3 years ago
7

Which property is shown in the matrix addition below?

Mathematics
2 answers:
posledela3 years ago
5 0

Answer: Choice C) Inverse


Specifically this is the additive inverse. Note how each element adds to its corresponding pair to add to zero (eg: -6+6 = 0 in row1, column1). The additive inverse of x is the number -x. So x+(-x) = 0.

alex41 [277]3 years ago
5 0

it is inverse property (A)

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Y=99.99+23.75(x-1) as a Y=ax+b equation
Hatshy [7]

Answer:

y = 23.75x  + 76.24

Step-by-step explanation:

We want to rewrite

y = 99.99 + 23.75(x - 1)

in the form

y = ax + b

We expand to get:

y = 99.99 + 23.75x - 23.75

Regroup similar terms:

y = 23.75x - 23.75 + 99.99

Simplify:

y = 23.75x  + 76.24

This is now of the form

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If there are 52 cards in a deck with four suits (hearts, clubs, diamonds, and spades), how many ways can you select 5 diamonds a
Luba_88 [7]

Answer:

12C5 *(12C3) = 792*220 =174240 ways

Step-by-step explanation:

For this case we know that we have 12 cards of each denomination (hearts, diamonds, clubs and spades) because 12*4= 52

First let's find the number of ways in order to select 5 diamonds. We can use the combinatory formula since the order for this case no matter. The general formula for combinatory is given by:

nCx = \frac{n!}{x! (n-x)!}

So then 12 C5 would be equal to:

12C5 = \frac{12!}{5! (12-5)!}=\frac{12!}{5! 7!} = \frac{12*11*10*9*8*7!}{5! 7!}= \frac{12*11*10*9*8}{5*4*3*2*1}=792

So we have 792 was in order to select 5 diamonds from the total of 12

Now in order to select 3 clubs from the total of 12 we have the following number of ways:

12C3 = \frac{12!}{3! 9!}=\frac{12*11*10*9!}{3! 9!} =\frac{12*11*10}{3*2*1}=220

So then the numbers of ways in order to select 5 diamonds and 3 clubs are:

(12C5)*(12C3) = 792*220 =174240 ways

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