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lukranit [14]
3 years ago
8

Factorise x^3 - 3x^2 - 9x - 5​

Physics
1 answer:
Anuta_ua [19.1K]3 years ago
8 0

Answer:

(x +1), (x -5) and (x +1)

Explanation:

The computation of the factorization is shown below

Data provided in the question

X^3 - 3x^2 - 9x - 5

Based on the above information, the factors are

Now we have to open these equations in order to get the factors which are as follows

= x^3 + x^2 - 4x^2 - 4x - 5x - 5

= x^2( x + 1) - 4x ( x + 1) - 5(x + 1)

= (x + 1) (x^2 - 4x - 5)

= (x + 1)(x^2 -5x + x - 5)

So,

= (x + 1) (x - 5) (x + 1)

Therefore the (x +1), (x -5) and (x +1) are the factors of the mention polynomial give in the question

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