All categories

3 years ago

What is the momentum of a 3 kg bowling ball moving at 3 m/s?

Physics

1 answer:

Nataly [62]3 years ago

5 0

Explanation:

p denotes momentum
m denotes mass
v denotes velocity

→ p = 3 kg × 3 m/s

→ p = 9 kg.m/s

Option D is correct.

You might be interested in

Calculate the pressure on the bottom of a swimming pool 3. 5 m deep. How does the pressure compare with atmospheric pressure, 10

Nostrana [21]

Answer:

1.343 atm

Explanation:

The mass of water above 1 square meter of swimming pool bottom is ...

M = (3.5 m)·(1000 kg/m^3) = 3500 kg/m^2

Then the force exerted by the water on the pool bottom is ...

F = Mg = (3500 kg/m^2)(9.8 m/s^2) = 34300 N/m^2 = 34300 Pa

Compared with atmospheric pressure, this is ...

34,300/10^5 = 0.343 . . . . atmospheres

Added to the atmospheric pressure on the water's surface, the total pressure on the pool bottom is 1.343 atmospheres.

5 0

4 years ago

Please help don’t know how to show my work

Fudgin [204]

Answer:

64.50816

Explanation:

3 0

3 years ago

Davahl is interested in tortoises because they can live for over a hundred years and have unique metabolisms. She wants to perfo

lesya [120]

I would say its time

4 0

3 years ago

Read 2 more answers

What is the critical mass of a species?

NemiM [27]

Answer:

I am fairly certain it is A but i would wait for an expert to answer

4 0

3 years ago

Light shines through a single slit whose width is 5.7 x 10-4 m. A diffraction pattern is formed on a flat screen located 4.0 m a

lilavasa [31]

Answer:

$\lambda = 570\ nm$

Explanation:

Given,

Width of slit, W = 5.7 x 10⁻⁴ m

Distance between central bright fringe, L = 4 m

distance between central bright fringe and first dark fringe, y = 4 mm

Diffraction angle

$tan \theta = \dfrac{y}{L}$

$tan \theta = \dfrac{4}{4\times 10^3}$

$\theta = 0.0572$

Now.

$W sin \theta = m \lambda$

m = 1

$5.7 \times 10^{-4} \times sin (0.0572) = 1 \times \lambda$

$\lambda = 569.99 \times 10^{-9}\ m$

$\lambda = 570\ nm$

4 0

3 years ago